Lattice energy value can be positive or negative.
Lattice formation energy released : negative value
Lattice breaking energy absorbed : positive value.
b) Given the following data, calculate the lattice energy for silver iodide. Enthalpy of sublimation of...
Given the following information, calculate the lattice energy of CaF2 The enthalpy of formation of CaF2 -1228 kJ/mol Heat of sublimation of Ca 177.8 kJ/mol Bond dissociation energy of F2 159 kJ/mol First ionization energy of Ca 589.8 kJ/mol Second ionization energy of Ca 1145.4 kJ/mol . Electron affinity of F -328 kJ/mot [ Answer : -2644 KJİ I
Using the data given below, sketch a Born-Haber cycle for the formation of BaC2(s) and insert the various equations and energy values into the individual steps of your cycle Sublimation energy for Ba(s) +180 kJmol1 Electron affinity for Cl(g)-346 kJmol1 First ionization energy for Ba(g)-+514 kJmol1 Bond dissociation energy for Clh(g) +243 kJmol Enthalpy of formation of BaCl2: Ba(s) + Ch(g) BaCh(s)--610 kJmol Lattice energy. Ba2+(g) + 2Cl.(g) → BaCl2(s)--2075 kJmol-1 Calculate the second ionization energy for Ba+(g) → Ba2+(g)...
Calculate the lattice energy for LiF(s) given the following: sublimation energy for Li(s) = +166 KJ/mol delta Hf for F(g) = +77 KJ/mol first ionization energy of Li(g) = +520 KJ/mol electron affinity of F(g) = -328 KJ/mol enthalpy of formation of LiF(s) = -617 KJ/mol
2. Use the following data to calculate the lattice energy (U) of NaCl(s) from sodium me chlorine: Enthalpy of formation (4H) for NaCl(s) - -411 kJ/mol Enthalpy of sublimation (4Hub) of Na 107.3 kJ/mol The first ionization energy of Na (E,)-495.8 kJ/mol The bond dissociation energy (D) of Clh- 243 kJ/mol The electron affinity of Cl (Eea)- 348.6 kJ/mol.
Using the Born Haber cycle in the previous question, and the following energies, calculate the standard energy of formation for Srl2 Enthalpy of sublimation of Sr(s) = 164 kJ/mol 1st ionization energy of Sr(g) = 549 kJ/mol 2nd ionization energy of Sr(g) - 1064 kJ/mol Enthalpy of sublimation of 12(s) = 62 kJ/mol Bond dissociation energy of 12(g) - 153 kJ/mol 1st electron affinity of l(g) = -295 kJ/mol Lattice energy of Srlz(s) = -1960 kJ/mol *Note: Do not include...
Consider the following information. The lattice energy of NaCl is ΔH lattice=−788 kJ/mol The enthalpy of sublimation of Na is ΔHsub=107.5 kJ/mol The first ionization energy of Na is IE1=496 kJ/mol. The electron affinity of Cl is ΔHEA=−349 kJ/mol. The bond energy of Cl2 is BE=243 kJ/mol. Determine the enthalpy of formation, ΔHf, for NaCl(s). ΔHf= kJ/mol
5. Calculate the lattice energy for barium bromide given that AH, for this compound is -757.3 kJ mol, the entropy of sublimation of barium is 180. kJ molt, the electron affinity for bromine is -324.5 kJ mol", the first lonization energy of barium is 502.8 kJ mol", the second lonization energy of barium is 965.2 kJ moll, and the heat of vaporization of bromide is 30.9 kJ mol (6 pts)
5. Calculate the lattice energy for barium bromide given that AH, for this compound is -757.3 kJ mol, the entropy of sublimation of barium is 180. kJ molt, the electron affinity for bromine is -324.5 kJ mol", the first lonization energy of barium is 502.8 kJ mol", the second lonization energy of barium is 965.2 kJ moll, and the heat of vaporization of bromide is 30.9 kJ mol (6 pts)
Calculate the lattice enthalpy of AgCl (s) using the following thermodynamic data. Note that the data given has been perturbed, so looking up the answer is probably not a good idea. Cl - Cl (g) Enthalpy of dissociation = 223 kJ/mol Ag (g) Enthalpy of formation = 265 kJ/mol Cl (g) Electron attachment enthalpy = -369 kJ/mol Ag (g) Enthalpy of ionization = 711 kJ/mol AgCl (s) Enthalpy of formation = -147 kJ/mol kJ/mol
Consider the following information. The lattice energy of LiCl is ΔH lattice = −834 kJ/mol. The enthalpy of sublimation of Li is ΔH sub = 159.3 kJ/mol. The first ionization energy of Li is IE 1 = 520 kJ/mol. The electron affinity of Cl is ΔH EA = -349 kJ/mol. The bond energy of Cl2 is BE = 243 kJ/mol. Determine the enthalpy of formation, ΔHf, for LiCl(s).