Molarity CaCO3(s)
Ca2+(aq) + CO32-(aq)
Initial 0 0
Change x x
Final x x
Now, Ksp = [Ca2+] [CO32-]
4.96 x 10-9 = (x)(x)
x2 = 4.96 x 10-9
x = (4.96 x 10-9)
x = 7.04 x 10-5
So, molar solubility of CaCO3 = 7.04 x 10-5
Answer is (a)
Please show how you got your answer so I can understand what you did:) thanks! Calculate...
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