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20. Calculate the MOLAR SOLUBILITY of silver bromide (Kp - 5.40 x 1013) in 1.0 M NH. Complex ion [Ag(NHs)2] can be formed (K,
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Answer #1

21 Reaction - AgBocs+ 2NH3a, [Ag CN13),]++ Bian ...) At equillibrium, [Ag (NH3) + +Br = x Thus [NHBJ = 1-22 . [Ntb] = 1 m. K=

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please explain how you got all your answers 20. Calculate the MOLAR SOLUBILITY of silver bromide...
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