Question

45 and 46 explained pls. correct answers are chosen

45) What is the molar solubility of calcium carbonate (CaCO3) in water? The solubility product constant for CaCO3 is 4.5 x 10-9 at 25 °C. A) 9.0 x 10-9 B) 2.3 x 10-9 C) 8.35 D) 9.5 x 10-5 (E)6.7 x 10-5 46) 46) In which of the following aqueous solutions would you expect AgF to have the lowest solubility? A) 0.030 M LIF B) 0.015 M KF C) 0.023 M NaF D) pure water E) 0.0075 M AgNO3

Answer 1

S molas solubility. (5) (5) - [621772829 Ksp = Solubility product 522 Ksp as Sarkse S = √ (4.5X10-9) - 6,7x10-5 . Molar solubility is: 6 6.7x10-5 46 It is due to common in effect. lif has Prion Common with AGF eo Now, f - Concentration as given in question is manimum in 0.030 m Lif, so Agf is lowest soluble