a)
=
X / n = 65.39
b)
S = sqrt [
X2 - n
2
/ (n-1) ] = 1.6802
c)
H0:
= 61.3
Ha:
> 61.3
Test statistics
t = (
-
) / ( S / sqrt ( n) )
= ( 65.39 - 61.3) / ( 1.6802 / sqrt(10) )
= 7.70
d)
From Table,
With df of 9 and significance level of 0.01,
Critical value = 2.821
e)
Since test statistics > 2.821 , reject H0.
There is sufficient evidence to support the claim that, with the enriched fee, the mean weight
is greater than 61.3
(2 points) When a poultry farmer uses his regular feed, the newborn chickens have normally distributed...
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Keep at 4th decimal place
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