- Carcurdle mne new sup at which the maximum torque occurs 0.2617 QUESTION 11 A 460-V....
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per phase referred to the stator circuit. Ri= 0.212 R2 = 0.282 X1 = 1.055 12 X2 = 1.055 22 XM = 33.9 W The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped with the rotational losses. For a rotor slip of 4% at the rated voltage and rated frequency, a) The input power b) Peony...
4.6. A 460-V, 75 kW, 4-pole, delta-connected, 60-Hz, three- phase induction motor has a full-load slip of 5 percent, an efficiency of 92 percent and a power-factor of 0.87 lagging at full-load. At start-up, the motor develops 1.9 times the full load developed torque but draws 7.5 times the rated current at the rated voltage. This motor is to be started with an auto- transformer reduced-voltage starter. Assume the stator resistance and the stator core loss to be negligible. Calculate...
3c) Induction Machine Analysis [ 8 marks ] A 415 V, 50 Hz, 1450 rpm, three-phase, star-connected induction machine has the following equivalent circuit parameters (referred to the stator winding where appropriate) stator resistance R 0.3 ohms, rotor resistance R2 0.2 ohms stator leakage reactance X 2 ohms, rotor leakage reactance X2' 2 ohms magnetising reactance XM 50 ohms, core loss resistance Rc 200 ohms In your calculations, you should use = the simplified equivalent circuit i) Find the number...
A 4 phase, 460 V, 60 Hz, 26.8 hp, 4 pole, Y-connected induction motor draws 25 A at a power factor of 0.9 lagging. Core loss is 900 W, stator copper loss is 1100W, friction and winding losses are 300 W, and stray loss is neglected. The machine shaft rotates at 1738 rpm. Calculate the air gap power and output load torque - [Induction Motor - 15 points) A three-phase, 460 V, 60 Hz, 26.8 hp, 4-pole, Y-connected induction motor...
6.12 A three-phase, Y-connected, 460-V (line-line), 37-kW, 60-Hz, four-pole induction motor has the following equivalent-circuit parameters in ohms-per-phase referred to the statr: R10.070 R2 0.152 X 0.743 X2 0.764 Xm 40.1 The total friction and windage losses may be assumed constant at 390 W, and the core loss may be assumed to be equal to 325 W. With the motor connected directly to a 460-V source, compute the speed, output shaft torque and power, input power, and power factor and...
[3] A three-phase 11.2 kW Y connected induction motor has the following parameters: 460 V, 60 Hz, 4-pole, 1750 rpm. R,-0.382, X1.142, X, - 1.71 2, and X. = 33.2 2. The motor is controlled by stator frequency scalar control method using VSI. Calculate the new values of breakdown torque. if the supply frequency is 65 Hz and 75 Hz respectively. Neglect the stator resistance.
Can you make sure solution has the answer that is stated above on the right 3. A 3ф, 460 V, 60 Hz, 50 hp, 1180 rpm induction motor has the following parameters: Ts-0.191 ohms, -0.0707 ohms, Lis 2 mH, (stator leakage inductance) Lr 2 mH (rotor leakage inductance, referred to stator) Lm 44.8 mH Determine the values of the rated stator current Is and rated motor torque Te using the exact T equivalent circuit. Hint: a motor reactance X-jaeL Answer:...
6. [Induction Motor - 15 points] A three-phase, 460 V, 60 Hz, 26.8 hp, 4-pole, Y-connected induction motor draws 25 A at a power factor of 0.9 lagging. The core loss is 900 W, stator copper loss is 1100 W, friction and windage loss is 300 W, and stray loss is neglected. The machine shaft rotates at a speed of 1738 rpm. Calculate the air gap power and output load torque.
Example 20-4. A 200 hp (150 kW), 460 V, 3-phase, 3520 r/min, 60 Hz induction motor has a locked-rotor torque of 600 Nom and a locked-rotor current of 1400 A (same motor as in Example 20- 2). Two autotransformers, connected in open delta, and having a 65 percent tap, are employed to provide reduced-voltage starting. Calculate a. The apparent power absorbed by the motor b. The apparent power supplied by the 460 V line c. The current supplied by the...
Consider a 50 kW, 3-phase, 380 V line-to-line, 50 Hz, 6 pole Y-connected wound-rotor induction motor. The stator winding ac resistance is 0.1 Ω/phase. The effective stator-to-rotor turns ratio is 2. The exciting branch is negligible. It is found that when an external resistor of 0.09 Ω/phase is connected to the rotor terminals maximum starting torque of 1150 Nm is obtained. a. Compute the internal mechanical power and the internal torque developed by this motor when it drives a load...