Question

As a result of an experiment following measurements were obtained from a cell: intracellular Na* concentration of 10 mm, intracellular K* concentration of 140 mm, intracellular Cl' concentration of 5 mm, interstitial Na* concentration of 150 mm, interstitial K concentration of 5 mm, interstitial Cl' concentration of 120 mm, relative potassium/sodium permeability of 32. Using these values calculate membrane potential of these cells. (RT/F = 26.7 mV, 37°C) (5 pts). Select one: a. -71 mV b. +71 mv C. +43 mV d. -43 mv

According to biophysics

Answer 1

In the experiment Na+, K+ and Cl- are the contributors to the membrane potential in a cell.

In my Allonding to Goldman - Hodgkin kafe equation. membrane potential COM Pk [kyo epwa [vál]o e PCIeci PR (t]pwe(); Freizile R > 8.314 Jkl moti Em: Rela F 310.15€. 33°C 6273.15 = T » 968 45 c-mol-1 f PKIPNA, PCI Relative permeability [K] concentration of it in extracellule fluid a concentration of kf in intracellular concentration of Nat in interstitial (wal); ₂ concentration of Nat in intracellular. concentration of ci in extra collalas Concentration of ci in into acollidor (ke); (Nat). [cr]. (C1);- cell af aest Pk :P Nat Pol = 1:005:0.45 CS Jozanned with CamScanner

R1 26.2 mu N exst 0.08x150 7 092x 5 Ema 26.2 8V en horst Isop 0.92x120 1.6x10.0-0801 - -43 my CS Scanned with CamScanner