if t < 41 8(t) = 41 if t > 41 Solve the differential equation y(0)...
Question 5 < > Given the differential equation y' + 5y' + 4y = 0, y(0) = 2, y'(0) = 1 Apply the Laplace Transform and solve for Y(8) = L{y} Y(s) = Now solve the IVP by using the inverse Laplace Transform y(t) = L-'{Y(s)} g(t) =
(1 point) Solve the differential equation -1, y (0)2 y-4y -5t263 (t) y(0) using Laplace transforms. for 0 t3 The solution is y(t and y(t) for t> (1 point) Solve the differential equation -1, y (0)2 y-4y -5t263 (t) y(0) using Laplace transforms. for 0 t3 The solution is y(t and y(t) for t>
differential equations Problem 2 Solve y"+y= ſt/2, if 0 <t<6, if t > 6 y(0) = 6, 7(0) = 8
Solve y'' + 4y = $(t – 6), y(0) = y'(0) = 0 g(t) = for t < 6 fort > 6
Solve the given integral equation or integro-differential equation for y(t). y'CL)+ 125 ſ <t-vy(v) dv=7! y(0)=0 0 y(t) = Enter your answer in the answer box.
Find the Laplace transform of the function f(t). f(t) = sint if 0 St< $41; f(t) = 0 ift> 41 Click the icon to view a short table of Laplace transforms. F(s)=
(1 point) Let Solve the differential equation using Laplace transforms. t/16-sin(4t)/64+3/4sin(4t)+4cos(4t) ft 4T y(t) = ift>4 -cos(4t)/16+1/16+3/4sin(4t)+4cos(4t)
Solve the y"+ 4y = initial value problem s 1 if 0<xsa To if x>,T ylo)= 1, g(0)=0
Q4 a) Find the general solution of the differential equation Y') + {y(t) = 8(6+1)5; 8>0. Y'8 8 >0. 8(8-1)3 b) Find the inverse Laplace transform y(t) = £ '{Y(3)}, where Y(s) is the solution of part (a). c) Use Laplace transforms to find the solution of the initial value problem ty"(t) – ty' (t) + y(t) = te, y(0) = 0, y(0) = 1, for t > 0. You may use the above results if you find them helpful....
y(t)=? Solve the following differential equation by Laplace transforms. The function is subject to the given conditions. y'' +81y = 0, y(0) = 0, y'(0) = 1 Click the icon to view the table of Laplace transforms. y = (Type an expression using t as the variable. Type an exact answer.)