The decomposition of in is a first-order reaction. If 1.77 mg of is present initially and 1.71 mg is present after 5.98 minutes at 55 °C, what is the value of the rate constant?
Answer:-
The reaction is first order reaction.
[A]o = 1.77 mg
[A]t = 1.71 mg
t = 5.98 min
k = 2.303/t log[A]o/[A]t
= 2.303/5.98 x log(1.77/1.71)
= 0.00577 min-1
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