The decomposition of ethane (C2H6) to methyl radicals is a first-order reaction with a rate constant of 5.36 X 10^-4 s ^-1 at 700˚C: C2H6 ---> 2CH3. Calculate the half-life of the reaction in minutes.
We know that
for first order reaction
Half life t1/2 = 0.693 / rate constant k
So Half Life
t1/2 = 0.693 / (5.36 x 10-4 s-1)
= 1292.91 s
= 1292.91 /60 min
= 21.55 min
Therefore half life in min = 21.55 min
The decomposition of ethane (C2H6) to methyl radicals is a first-order reaction with a rate constant...
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