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A proton enters a parallel-plate capacitor traveling to the right at a speed of 1.276 x 10-5 m/s, as shown in the figure. The

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solution Ginen initial speed of proton (u) = 1.226410 m/s separation of two plates = 1:62cm = 1062x102m Electric Jield (E) =ge = (1.27681052 + 2x 2.82 x 104, 01810 81652 z = 1.628 176 8 10 10 + 4.568 4x106 Ug = 0.000 16 x 156 + 4+ 568x106 = 4.568x10Dear friend if you have any doubts leave a comment...

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