Question

(b) Prove that at each step of the Fibonacci search algorithm, p<q Hint: Prove the cases k-n (Step 2), k-n - 1,n - 2,...,3 (S

Fibonacci search algorithm

Fibonacci Search Algorithm To minimise a continuous unimodal function f over [a, b] to within tolerance . O Find the smallestB Set kk -1. If f (p) < f(q), then set (2.19) (2.20) (2.21) 9-p Fk-1 Fk Calculate f(p). If f (p) >f(g), then set (2.22) (2.23If f(p) f(q), then set 4 (2.25) (2.26) (2.27) q=p p=b_2e Calculate f(p). If f(p) > f(q), then set (2.28) (2.29) (2.30) p=q Caif f(p) f(q), then b q If f(p)> f(), then ap. The final interval is [a, b]. This interval has length either 2 or

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Answer #1

i didn't understand what you want

c code for fibonacci series is with different conditions

#include <stdio.h>
int main()
{
  int Number, i = 0, Next, First_Value = 0, Second_Value = 1;

  printf("\n Please Enter the Range Number: ");
  scanf("%d",&Number);
  
  while(i < Number) 
  {
        if(i <= 1)
        {
                Next = i;
        }
        else
        {
                Next = First_Value + Second_Value;
                First_Value = Second_Value;
                Second_Value = Next;
        }
    printf("%d \t", Next);
        i++;  
  }
  return 0;
}
//2
#include <stdio.h>

int main() {
   int a, b, c, i, n;

   n = 4;

   a = b = 1;
   
   printf("%d %d ",a,b);

   for(i = 1; i <= n-2; i++) {
      c = a + b;
      printf("%d ", c);
      
      a = b;
      b = c;
   }
   
   return 0;
}

//3

// Fibonacci Series using Recursion
#include <stdio.h>
int fib(int n)
{
   if (n <= 1)
       return n;
   return fib(n - 1) + fib(n - 2);
}

int main()
{
   int n = 9;
   printf("%d", fib(n));
   getchar();
   return 0;
}

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