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102 PROPO344: Molecular Mass Determination by Freezing Point Depression in t-Butyl Alcohol 3. A student determined...
for question 1 the molar mass of unknown is 102g/mol hation by Freezing Point Depression Vernier...
for
question 1 the molar mass of unknown is 102g/mol
hation by Freezing Point Depression Vernier Logger Pro for Windows Section Post-Laboratory Questions (Use the space provided and additional paper if necessary. Record your nemerical answers in the boxes provided.) 1. Obtain the correct molar mass of your unknown from your laboratory instructor. Calculate the percent error in the molar mass that you found. Torg/mol percent error, 2. A student determined the freezing point of pure t-butyl alcohol following the...
A freezing point depression experiment was conducted using tert-butyl alcohol as the solvent instead of water...
A freezing point depression experiment was conducted using tert-butyl alcohol as the solvent instead of water The freezing point of pure tert-butyl alcohol is 27C and Kf=9.1C/mol. To 25g of tert-butyl alcohol was added 0.70 g of a non-electrolyte solute (i.e. sugar). The solution was cooled and the new freezing point was determined to be 20C. 1. What is the molar mass of the unknown non-electrolyte solute? 2. In a similar experiment, MgCl2 (MW= 95.2 g/mol) solute was added to...
Freezing Point Depression: Determination of the Molar Mass of an Unknown Substance Laboratory Record Unknown Identifier...
Freezing Point Depression: Determination of the Molar Mass of an Unknown Substance Laboratory Record Unknown Identifier #4 (All unknowns are nonelectrolytes, soi-1) Determination of the freezing point of pure l-butyl alcohol: (Record time-temperature data on the next page) 29.62 1. Mass of empty test tube 2. Mass of test tube and t-butyl alcohol after determination of freezing point of pure t-butyl alcohol 50.25 20.71 3. Mass of t-butyl alcohol Determination of the molar mass of an unknown: (Record time-temperature data...
A student weighs out 1.394 g of t-butyl alcohol into a large test tube and measures...
A student weighs out 1.394 g of t-butyl alcohol into a large test tube and measures the freezing point of the pure solvent to be 21.50 °C. Next the student weighs out 1.068 g of water and adds it to the test tube with the t-butyl alcohol and measures the freezing point of the mixture to be 15.0 °C. What is the freezing point depression constant, Kf, of the t-butyl alcohol?
Chemistry: Molar mass determination and freezing point depression. If your unknown solute sample weighed 0.634 grams,...
Chemistry:
Molar mass determination and freezing point depression.
If your unknown solute sample weighed 0.634 grams, but some of it stuck to the test tube wall when you were pouring it in and did not dissolve in the t-butyl alcohol, what sort of error will this cause in the calculated molar mass of your unknown solute? Explain. What would be the freezing point of an aqueous solution that contains 10.3 grams of ethylene glycol [(C_2H_4(OH)_2] in 100 mL of water?
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a...
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a solution of 65.1 g ethylene glycol (C2H602) in 792 g H20. Kffor H2O is 1.86 °C kg/mol. °C 1homework pts Submit Answer Tries 0/5 A solution which contains 60.9 g of an unknown molecular compound in 325 g of water freezes at -3.24°C. What is the molar mass of the unknown? g/mol 1homework pts Submit Answer Tries 0/5
Determination of Molar Mass by freezing Point depression Not sure how to answer these two questions...
Determination of Molar Mass by freezing Point depression
Not sure how to answer these two questions
Calcium chloride, CaCI_2 is commonly used as road salt. If one mole of CaCI_2 is dissolved in 1 kg v of water, would the freezing point of the solution be greater than, less than, or the same as a solution prepared by dissolving one mole of table sugar (sucrose, C_12H_22O_11) in 1 kg of water? Explain your answer. A student followed our lab procedure...
The molar mass of unknown molecular compound is determined using freezing point depression. The substance is...
The molar mass of unknown molecular compound is determined using freezing point depression. The substance is dissolved in benzene (C6H), an organic solvent. Use the data below to determine the molar mass of the substance. 8.65 g Mass of unknown compound Freezing point of solution Volume of benzene -10.21°C 35.0 mL 5.53°C Freezing point of benzene Density of benzene Kf for benzene 0.8765 g/mL 5.12°C/m Molar mass = g/mol
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a...
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a solution of 57.6 g ethylene glycol (C2H602) in 734 g H20. Kffor H20 is 1.86 °C kg/mol. °C -2.53 1 homework pts Submit Answer Incorrect. Tries 3/5 Previous Tries A solution which contains 71.9 g of an unknown molecular compound in 363 g of water freezes at -3.85°C. What is the molar mass of the unknown? g/mol 1homework pts Submit Answer Tries 0/5 Molar...
Molar mass determination by depression of freezing point lab I'm stuck on calculating the moles of...
Molar mass determination by depression of freezing point lab I'm
stuck on calculating the moles of solute.. How do I calculate it?
Also can u please check if I've done everything else correctly..
The data I collected: Measured freezing point of pure water: 0.0
degrees Celsius Actual mass of solute used: 10.12g Freezing point
of solution (observed): -3.4 Celsius Mass of solution: 84.7g
Freezing point of a Solution of liqud unknown Freezing point depression: Trial #1. 0.0℃ (-3.4°C)= 3.4℃ Molality...
for
question 1 the molar mass of unknown is 102g/mol
hation by Freezing Point Depression Vernier Logger Pro for Windows Section Post-Laboratory Questions (Use the space provided and additional paper if necessary. Record your nemerical answers in the boxes provided.) 1. Obtain the correct molar mass of your unknown from your laboratory instructor. Calculate the percent error in the molar mass that you found. Torg/mol percent error, 2. A student determined the freezing point of pure t-butyl alcohol following the...
Freezing Point Depression: Determination of the Molar Mass of an Unknown Substance Laboratory Record Unknown Identifier #4 (All unknowns are nonelectrolytes, soi-1) Determination of the freezing point of pure l-butyl alcohol: (Record time-temperature data on the next page) 29.62 1. Mass of empty test tube 2. Mass of test tube and t-butyl alcohol after determination of freezing point of pure t-butyl alcohol 50.25 20.71 3. Mass of t-butyl alcohol Determination of the molar mass of an unknown: (Record time-temperature data...
Chemistry:
Molar mass determination and freezing point depression.
If your unknown solute sample weighed 0.634 grams, but some of it stuck to the test tube wall when you were pouring it in and did not dissolve in the t-butyl alcohol, what sort of error will this cause in the calculated molar mass of your unknown solute? Explain. What would be the freezing point of an aqueous solution that contains 10.3 grams of ethylene glycol [(C_2H_4(OH)_2] in 100 mL of water?
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a solution of 65.1 g ethylene glycol (C2H602) in 792 g H20. Kffor H2O is 1.86 °C kg/mol. °C 1homework pts Submit Answer Tries 0/5 A solution which contains 60.9 g of an unknown molecular compound in 325 g of water freezes at -3.24°C. What is the molar mass of the unknown? g/mol 1homework pts Submit Answer Tries 0/5
Determination of Molar Mass by freezing Point depression
Not sure how to answer these two questions
Calcium chloride, CaCI_2 is commonly used as road salt. If one mole of CaCI_2 is dissolved in 1 kg v of water, would the freezing point of the solution be greater than, less than, or the same as a solution prepared by dissolving one mole of table sugar (sucrose, C_12H_22O_11) in 1 kg of water? Explain your answer. A student followed our lab procedure...
The molar mass of unknown molecular compound is determined using freezing point depression. The substance is dissolved in benzene (C6H), an organic solvent. Use the data below to determine the molar mass of the substance. 8.65 g Mass of unknown compound Freezing point of solution Volume of benzene -10.21°C 35.0 mL 5.53°C Freezing point of benzene Density of benzene Kf for benzene 0.8765 g/mL 5.12°C/m Molar mass = g/mol
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a solution of 57.6 g ethylene glycol (C2H602) in 734 g H20. Kffor H20 is 1.86 °C kg/mol. °C -2.53 1 homework pts Submit Answer Incorrect. Tries 3/5 Previous Tries A solution which contains 71.9 g of an unknown molecular compound in 363 g of water freezes at -3.85°C. What is the molar mass of the unknown? g/mol 1homework pts Submit Answer Tries 0/5 Molar...
Molar mass determination by depression of freezing point lab I'm
stuck on calculating the moles of solute.. How do I calculate it?
Also can u please check if I've done everything else correctly..
The data I collected: Measured freezing point of pure water: 0.0
degrees Celsius Actual mass of solute used: 10.12g Freezing point
of solution (observed): -3.4 Celsius Mass of solution: 84.7g
Freezing point of a Solution of liqud unknown Freezing point depression: Trial #1. 0.0℃ (-3.4°C)= 3.4℃ Molality...
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