A student weighs out 1.394 g of t-butyl alcohol into a large test tube and measures the freezing point of the pure solvent to be 21.50 °C. Next the student weighs out 1.068 g of water and adds it to the test tube with the t-butyl alcohol and measures the freezing point of the mixture to be 15.0 °C. What is the freezing point depression constant, Kf, of the t-butyl alcohol?
A student weighs out 1.394 g of t-butyl alcohol into a large test tube and measures...
A freezing point depression experiment was conducted using tert-butyl alcohol as the solvent instead of water The freezing point of pure tert-butyl alcohol is 27C and Kf=9.1C/mol. To 25g of tert-butyl alcohol was added 0.70 g of a non-electrolyte solute (i.e. sugar). The solution was cooled and the new freezing point was determined to be 20C. 1. What is the molar mass of the unknown non-electrolyte solute? 2. In a similar experiment, MgCl2 (MW= 95.2 g/mol) solute was added to...
102 PROPO344: Molecular Mass Determination by Freezing Point Depression in t-Butyl Alcohol 3. A student determined the K of t-butyl alcohol using tap water instead of distilled or deionized water. Describe the problems that might have been encountered. How would these problems affect the magnitude of K?
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question 1 the molar mass of unknown is 102g/mol
hation by Freezing Point Depression Vernier Logger Pro for Windows Section Post-Laboratory Questions (Use the space provided and additional paper if necessary. Record your nemerical answers in the boxes provided.) 1. Obtain the correct molar mass of your unknown from your laboratory instructor. Calculate the percent error in the molar mass that you found. Torg/mol percent error, 2. A student determined the freezing point of pure t-butyl alcohol following the...
tert-Butyl alcohol is a solvent with a Kf of 9.10 °C/m and a freezing point of 25.5 °C.w liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 °C.Which of t Tiquid? View Available Hint(s) ethylene glycol (molar mass = 62.07 g/mol) 1-octanol (molar mass = 130.22 g/mol) glycerol (molar mass = 92.09 g/mol) 2-pentanone (molar mass = 86.13 g/mol) 1-butanol (molar mass = 74.12 g/mol) A protein subunit from an enzyme is part of a...
A student is determining the molar mass of an unknown compound based on the following data: mass compound: 4.80 g mass solvent (water): 0.022 kg new freezing point: -2.50 oC freezing point depression constant (Kf): 1.86 oC/molal (Freezing point of pure water = 0 oC) 0.0786 g/mol 162.33 g/mol 0.00616 g/mol 293.26 g/mol
Freezing Point Depression: Determination of the Molar Mass of an Unknown Substance Laboratory Record Unknown Identifier #4 (All unknowns are nonelectrolytes, soi-1) Determination of the freezing point of pure l-butyl alcohol: (Record time-temperature data on the next page) 29.62 1. Mass of empty test tube 2. Mass of test tube and t-butyl alcohol after determination of freezing point of pure t-butyl alcohol 50.25 20.71 3. Mass of t-butyl alcohol Determination of the molar mass of an unknown: (Record time-temperature data...
A. Data Test tube mass + glass + water: 84.74g Test tube mass + glass: 41.93g water mass: 42.81g mass of water in kilograms: 0.04281kg sacrose mass: 5.00g Kf water: 1.86C/m B. Graph data A: pure water cooling curve minutes with temperature 0minutes: 20.0C 1 minutes: 3.0C 2 minutes: 3.0C 3minutes: 1.0C 4minutes:1.0C 7 minutes:1.0C 8 minutes: 0C 11 minutes:0C 12 minutes:0C 13 minutes:-1C 14 minutes:-1C 15 minutes: -1C C. Graphic data B: solution cooling curve (sucrose and water) minutes...
Part II. Competing nucleophiles with t-butyl alcohol 1. The composition of the product mixture is analyzed based on refractive index measurem. At 20.0 °C, the refractive index of puret-butyl chloride is 1.3877 and that of pure 1-buty bromide is 1.4280. One previous student determined the refractive index of his product mixture to be 1.4250 at 20.0 °C. Assume a linear relation between the refractive index and the molar composition of the mixture. Calculate the molar percentages of t-butyl chloride and/-butyl...
Colligative Properties: Freezing Point Depression Lauris acid is added to a test tube and heated. The test tube is placed in water to freeze the lauric acid. After measuring the temperature, an unknown is added. The lauric acid and unknown are heated to a liquid and placed in cold water(Part B). In doing part B of this experiment, Group 1 removes the thermometer and stirring wire to add the unknown, and wipes them off, losing 0.25 g of lauric acid....
did i solve 1 a corectly or do my numbers need to be
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Test Tube M y 315 dilu LaiculdLIUIS PARTS B AND C Measuring the Freezing Points of Water and Aqueous Solutions 142 Laboratory Data for Determining Pring Pet T hree Decent Solutions Mass of Delonised Water salute Mass of Solute Freezing Point None 4.28 -1.84331 Naci 4, 4337 0.2380 -2.23293 Unknown A -0.2393 2.62978 Unknown B 4.04866 0.7395 -2.14573 1 Use the following steps to determine the...