Question

We can roughly model a gymnastic tumbler as a uniform solid cylinder of mass 08.0 kg and damelor 1.10 m Part A For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of A primitive yo yo If this tumbler rolls forward at 0700 rev/s, how much total kinetic energy does he have? Express your answer in joules. O AXO RO? Submit Request Answer Part B What percent of his total kinetic energy is rotational? Express your answer as a percentage. AEO OO? Kn

Answer 1

Given M = 68 kg d = 1.10m Radius R = a 2 = 1.10 R=0.55m w = 0.7 rev/s = 0-7X6-28 rad/s w = 4.396 radys (: I rev/s-6-28 rady Moment of Inertia of solid cylinder I = MR² Total Kinetic energy K7 = 1 0 27 1 Iw2 = 1 M (RW) + 12 (MR). we su= rol = 1 MRP w + / MRw2 (I= MR k = 2 MR W2 KT = 3 4 x 688 0.55² x 4.396² IKT = 298.133J Chus 2

© Rotational kinetic energy KR= 1 IW2 = 1 {MR2) W2_LRG KR = 0.3333 ke = 33.33%