Question

A Review Determine the magnitude of the z component of the reaction on the rod at B. Express your answer to three significant figures and include the appropriate units. View Available Hints) Learning Goal: To analyze a rod assembly in three-dimensional space and determine the support reactions by using the equations of equilibrium for a rigid body. The rod assembly shown has smooth journal bearings at A, 6 and C. The forces F = 650 N F = 500 N Fy = 140 N, and 1 - 800 N are applied as shown in the figure. The geometry of the rod assembly is given as a - 0.800 m. b-0.600 m, and C-0.700 m. Neglect the weight of the rod. | B = 316 N Submit Previous Answers X Incorrect; Try Again Part D - Finding the x component of the reaction at B Determine the magnitude of the x component of the reaction on the rod at B. Express your answer to three significant figures and include the appropriate units. View Available Hints) 1.= 166 N Submit Previous Answers X Incorrect; Try Again

Answer 1

Given data F2 = 500N F = 650N a: 0.800 m b= 0.60om F₂ = 4400 c=0.700m F4 = 800N By the equilibrium conditions of force and we can able to solve momentum EFx=0, Equating the forcy in x-direction AntBy =0 Ant Bn = F₂ = 500N {fy=0, Equating the forces in t direction - Cy - F3 =0 cy = F₂ = 44ON [cy=400N from the moment balance, EMX) O= - Fixa + B₂ (2a) + F3 (c) - Fu (30) tq (30) Substituting the valuy. 03-650 (08) + B z (240-8) + 440 (0:7)- 800(3x0.8) + C2 (380.8) O = -520+ B2 (16) + 308 - 1920 + Cz (2.4) - {my 70 = F (6) - Fu (a) + 22 (2a) Substituting the values 0 = 650(0.6)- 800 (0.8) + q (2x0,8) 0.390 - 640 + 2 ():6) C₂ (16)= 250 c2= 156.25 N

substituting a value in es to get B2 0 - 520+B2(1.6) + 308-1920 + 156-25 (26) D = -520+ B20-6) + 308 - 1920 + 375 B2 (1.6) = 520-308 + 1920-375 B2 (16)= 1757 B2 = 1098.125N Taking force Equilibrium along a dirution {F2=0. O= A2+ B 2 + (2- F4-F Az = -B2 - C + F4 + F1 - 1098.125 - 156.25 +800+650 = 195.625 N Az ~196N (AMS) Tating moment balance about 2-am's EM2 = 0= F (a)- Bxrea) + F3 (2) - cy (2a) Substituting the values 0 500 6.8) - Bx (2x0,8) +40 (0.8) - 600(8x08) Bx116) = 400 + 352-704 u8 Bn - 300 Bu= 300] Cons) Taking force balance along x-axis An= -Bn+F2 = -30+500 = 4700 Ax = 470 0 ] Ans)

Result (1) B₂ = 1098,125N (2) Br=30N (3) Az = 196 N (correct) [ As you get] (6) An= 470N SHE END -