A steel rod hangs vertically from a fixed support. The rod is 2.0m long and 1.5mm...
A steel rod hangs vertically from a fixed support. The rod is 2.0m long and 1.5mm in diameter. What mass hung from the rod will stretch it by 0.48mm ?
Homework Answers
Youngs modlulus Y of a material is given Y =
FL/ADL
A = area
here Y os steel is 2e11 N/m^2
DL = change of length
L = original length
F = force
so here we apply
F = YADL/L
F = mg = 2e11 * 3.14* (0.75*0.75e-6)*0.48 e-3/(2)
mg = 84.78
m = 84.78/9.8
m = 8.65 kgs
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