Answer:
Given that,
Length of the beam = 6 m
BE Part III (50pts) 1. Statically indeterminate beam (20pts) 24kN/m a)Express the external load 100KN function,...
#1) (65p.) Draw the Shear Force (V) and Bending Moment (M) diagrams of statically indeterminate beam shown in figure using “Force Method”. The (roller) support at “B” settles 35 mm. The moment of inertia is given by (I) for regions “AB”, “BC” and “CD”; however it is equal to (21) for the region “DE”. (“B” is the roller and “E” is the fixed type of support). [The flexural rigidity: EI=40000 kNm’] 60 KN 10 kN/m A B X (I) (I)...
#1) (65p.) Draw the Shear Force (V) and Bending Moment (M) diagrams of statically indeterminate beam shown in figure using “Force Method”. The (roller) support at “B” settles 35 mm. The moment of inertia is given by (I) for regions “AB”, “BC” and “CD”; however it is equal to (21) for the region “DE”. (“B” is the roller and “E” is the fixed type of support). [The flexural rigidity: EI=40000 kNm’] 60 KN 10 kN/m A B X (I) (I)...
#1) (65p.) Draw the Shear Force (V) and Bending Moment (M) diagrams of statically indeterminate beam shown in figure using “Force Method". The (roller) support at "B" settles 35 mm. The moment of inertia is given by (1) for regions "AB", "BC" and "CD"; however it is equal to (21) for the region "DE". ("B" is the roller and "E" is the fixed type of support). [The flexural rigidity: El-40000 kNm"] 60 KN 10 kN/m B (1) (1) D (21)...
#1) (65p.) Draw the Shear Force (V) and Bending Moment (M) diagrams of statically indeterminate beam shown in figure using "Force Method”. The (roller) support at “B” settles 35 mm. The moment of inertia is given by (I) for regions "AB", "BC" and "CD"; however it is equal to (21) for the region “DE”. (“B” is the roller and “E” is the fixed type of support). [The flexural rigidity: EI=40000 kNm] 60 KN 10 kN/m B (21) 1.5 m 1...
#1) (65p.) Draw the Shear Force (V) and Bending Moment (M) diagrams of statically indeterminate beam shown in figure using “Force Method”. The (roller) support at “B” settles 35 mm. The moment of inertia is given by (1) for regions "AB", "BC" and "CD"; however it is equal to (21) for the region “DE”. (“B” is the roller and "E" is the fixed type of support). [The flexural rigidity: EI=40000 kNm-] 60 KN 10 kN/m I. B (21) X 1.5...
#1) (65p.) Draw the Shear Force (V) and Bending Moment (M) diagrams of statically indeterminate beam shown in figure using "Force Method". The (roller) support at "B" settles 35 mm. The moment of inertia is given by (1) for regions "AB", "BC" and "CD": however it is equal to (21) for the region "DE". ("B" is the roller and "E" is the fixed type of support). [The flexural rigidity: EI-40000 kNm] 60 KN 10 kN/m B L (21) 1.5 X...
#1) (65p.) Draw the Shear Force (V) and Bending Moment (M) diagrams of statically indeterminate beam shown in figure using “Force Method”. The (roller) support at “B” settles 35 mm. The moment of inertia is given by (1) for regions “AB”, “BC” and “CD”; however it is equal to (21) for the region “DE”. (“B” is the roller and “E” is the fixed type of support). [The flexural rigidity: EI=40000 kNm?] 60 kN 10 kN/m 1 A B X (1)...
Part III 1. BEAM ANALYSIS (20pts) 6kips/ft E = 25 x 10° psi , l-200ìn4 1) Express the distributed weight, w(x). 2) Write the boundary conditions. 3) Solve the deflection curve. 4) Find the maximum moment. 5) Find the maximum deflection. お
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Statically Indeterminate Propped Cantilevered Beam Reaction and Deflection Derivation 1. Determine the reactions R4, Rg, and M, and the elastic equation for the section of the beam between the wall and the load P. 2. Note: It will take 3 solutions to solve for the elastic equations for the entire beam: 0<x<d, d<x<s, and s SXSL 1. The derivation of the elastic equation for the section between the wall and the load (0 <x<d) is derived above....
For the beam shown, assume that ET-130 ,000 kip-ft2, P = 80 kips, and w = 4.5 kips/ft. Use discontinuity functions to determine (a) the reactions at A, C, and D (b) the beam deflection at B Assume LAB = LBC = 9.0 ft, LCD = 18.0 ft. AB CD Sum the forces in the y direction to find an expression that includes the reaction forces Ay, Cy, and Dy acting on the beam. Positive values for the reactions are...