Question

u are free to use your notes and book, but ay access the internet to open your textbook. 1 pts D Question 42 A-7.32 D lens is held 14.2 cm from a 2.8 mm object. Where is the image located? 0 -6.56 cm O-718 cm 0 -696 cm -746 cm Next Previous Not saved Submit Quiz

Answer 1

Power of the lens=- 7.32 D

Hence , Focal length of the lens, f= 1/P= 1/-7.32 = -0.136 m =-13.66 cm

Now, Using the lens formula we have,

Power of the lens = -7.32 D Hence, Focal length of the lens, f = 1/P = 1/-7.32 = -0.136 m = -13.66 cm Now, Using the lens formula we have, 1/f = 1/u + 1/v where, u is the object distance and v is the image distance Therefore, 1/v = 1/f - 1/u = 1/ -13.66 -1/14.2 1/v = 1/-13.66 -1/14.2 = -0.1436 v = -6.96 cm Therefore, option third is the correct nation.

where, u is the object distance and v is the image distance

Therefore,

$\frac{1}{v}=\frac{1}{f}-\frac{1}{u}=\frac{1}{-13.66}-\frac{1}{14.2}$

$\frac{1}{v}=\frac{1}{-13.66}-\frac{1}{14.2}=-0.1436$

Therefore, option third is the correct nation.