Homework Answers
p̂ ± Z(α/2) √( (p * q) / n)
p̂ = X / n = 154/200 = 0.77
p̂ ± Z(α/2) √( (p * q) / n)
0.77 ± Z(0.1/2) √( (0.77 * 0.23) / 200)
Z(α/2) = Z(0.1/2) = 1.645
Lower Limit = 0.77 - Z(0.1) √( (0.77 * 0.23) / 200) = 0.721
upper Limit = 0.77 + Z(0.1) √( (0.77 * 0.23) / 200) = 0.819
90% Confidence interval is ( 0.7210 , 0.8190 )
( 0.7210 < P < 0.8190 )
Add Answer to:
In a random sample of 200 people, 154 said that they watched educational television. Find the...
In a random sample of 198 people, 170 said that they watched educational television. Find the...
In a random sample of 198 people, 170 said that they watched educational television. Find the 92% confidence interval of the true proportion of people who watched educational television.
In random, independent samples of 200 adults and 400 teenagers who watched a certain television show,...
In random, independent samples of 200 adults and 400 teenagers who watched a certain television show, 98 adults and 224 teens indicated that they liked the show. Let p1 be the proportion of all adults watching the show who liked it, and let P2 be the proportion of all teens watching the show who liked it. Find a 90% confidence interval for pi-p2. Then complete the table below. carry your intermediate computations to at least three decimal places. Round your...
A survey found that out of a random sample of 200 workers 168 said that they...
A survey found that out of a random sample of 200 workers 168 said that they were interruped 3 or more times an hour by phone messages, etc find the 90% confidence interval of the pop proportion of workers who are interupted 3 or more times
In random, independent samples of 400 adults and 325 teenagers who watched a certain television show,...
In random, independent samples of 400 adults and 325 teenagers who watched a certain television show, 244 adults and 159 teens indicated that they liked the show. Let P, be the proportion of all adults watching the show who liked it, and let P, be the proportion of all teens watching the show who liked it. Find a 95% confidence interval for P -P2. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round...
Suppose that a simple random sample of 145, 91 said they drink coffee in the morning....
Suppose that a simple random sample of 145, 91 said they drink coffee in the morning. Step 1 of 5: What is the sample proportion for people who drink coffee in the morning? Step 2 of 5: Do we have what we need to compute a confidence interval? Yes, it's binomial. Yes, n≥30. Yes, we have a simple random sample, it is binomial with n/.05 gives a value less than the number of people than that in the world, and...
7. Jose conducts a random sample of 41 people regarding their television viewing habits. He found...
7. Jose conducts a random sample of 41 people regarding their television viewing habits. He found that the sample mean was I = 4.615 hours per week with a sample standard deviation of s = 2.277 hours per week. Find a 90% confidence interval for the population mean. Nadide lines for ba t h ballot about
A random sample of n = 200 observations from a binomial population produced x = 190...
A random sample of n = 200 observations from a binomial population produced x = 190 successes. Find a 90% confidence interval for p. (Round your answers to three decimal places.) _______ to _______ Interpret the interval. 90% of all values will fall within the interval. There is a 10% chance that an individual sample proportion will fall within the interval. There is a 90% chance that an individual sample proportion will fall within the interval. In repeated sampling, 90%...
In a random sample of 24 people, the mean commute time to work was 32 minutes...
In a random sample of 24 people, the mean commute time to work was 32 minutes and t andard deviation was 7 minutes. Assume the population is normally debuted and use a distribution to constructa 99% confidence interval for the population mean what is the margin of error of Interpret the results The concerteval for the population means Round tone decimal places needed) The margin of error of Round to ore decimal place as needed) Interpret the results DAW concertante...
A random sample of forty-four 200-meter swims has a mean time of 3.62 minutes and the...
A random sample of forty-four 200-meter swims has a mean time of 3.62 minutes and the population standard deviation is 0.09 minutes. Construct a 90% confidence interval for the population mean time. Interpret the results. The 90% confidence interval is OD (Round to two decimal places as needed.) Interpret the results. Choose the correct answer below A. B. c. With 90% confidence, it can be said that the population mean time is not between the endpoints of the given confidence...
in a random sample of 24 people, the mean com m e to work was 32...
in a random sample of 24 people, the mean com m e to work was 32 confidence intervalo ne p o men. What is the margin of mor of and the standard the o ws Authe population is normally and ac tion to come The confidence in for the population meanis Round to one decimal place as needed) The margin of error of is Round to che decimal places needed) Interpret the results OA Win 99% confidence it can be...
In random, independent samples of 200 adults and 400 teenagers who watched a certain television show, 98 adults and 224 teens indicated that they liked the show. Let p1 be the proportion of all adults watching the show who liked it, and let P2 be the proportion of all teens watching the show who liked it. Find a 90% confidence interval for pi-p2. Then complete the table below. carry your intermediate computations to at least three decimal places. Round your...
In random, independent samples of 400 adults and 325 teenagers who watched a certain television show, 244 adults and 159 teens indicated that they liked the show. Let P, be the proportion of all adults watching the show who liked it, and let P, be the proportion of all teens watching the show who liked it. Find a 95% confidence interval for P -P2. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round...
7. Jose conducts a random sample of 41 people regarding their television viewing habits. He found that the sample mean was I = 4.615 hours per week with a sample standard deviation of s = 2.277 hours per week. Find a 90% confidence interval for the population mean. Nadide lines for ba t h ballot about
In a random sample of 24 people, the mean commute time to work was 32 minutes and t andard deviation was 7 minutes. Assume the population is normally debuted and use a distribution to constructa 99% confidence interval for the population mean what is the margin of error of Interpret the results The concerteval for the population means Round tone decimal places needed) The margin of error of Round to ore decimal place as needed) Interpret the results DAW concertante...
A random sample of forty-four 200-meter swims has a mean time of 3.62 minutes and the population standard deviation is 0.09 minutes. Construct a 90% confidence interval for the population mean time. Interpret the results. The 90% confidence interval is OD (Round to two decimal places as needed.) Interpret the results. Choose the correct answer below A. B. c. With 90% confidence, it can be said that the population mean time is not between the endpoints of the given confidence...
in a random sample of 24 people, the mean com m e to work was 32 confidence intervalo ne p o men. What is the margin of mor of and the standard the o ws Authe population is normally and ac tion to come The confidence in for the population meanis Round to one decimal place as needed) The margin of error of is Round to che decimal places needed) Interpret the results OA Win 99% confidence it can be...
Most questions answered within 3 hours.
-
1- What are 5 general characteristics of Botticelli’s
paintings?
2- Describe 5 important traits of Flemish...
asked 1 hour ago -
A golfer claims that his average golf score at the course he
plays regularly is less...
asked 2 hours ago -
On May 1, First Bank perfected a security interest in Debtor’s
inventory. On June 1, Bob...
asked 2 hours ago -
A new kind of typhoid shot is being developed by a medical
research team. The old...
asked 4 hours ago -
Write a chemical equation for these reactions. (Use
the lowest possible whole number coefficients.) Include
states-of-matter...
asked 6 hours ago -
For each of the Z-scores below, determine two probabilities
(show four three decimal places): (1) the...
asked 6 hours ago -
Oxidative phosphorylation is achieved through chemiosmotic
coupling, which turns chemical energy into osmotic potential energy
that...
asked 9 hours ago -
Hollywood Shoes would like to maintain their cash account at a
minimum level of $64,000, but...
asked 9 hours ago -
Proteins CtrA-P, DnaA, and GcrA behave similarly to what
molecule in the Eukaryotic Cell Cycle?
asked 9 hours ago -
TRUE OR FALSE
In case of a competitive tender procedure, in the request for
quotation, the...
asked 9 hours ago -
I am a little behind please provide some explanation, will
provide thumbs up.
This question considers...
asked 9 hours ago -
Let say the utility function as U(X,Y) = lnX + Y. Show that the
marginal rate...
asked 9 hours ago