In a random sample of 198 people, 170 said that they watched educational television. Find the...
In a random sample of 198 people, 170 said that they watched educational television. Find the 92% confidence interval of the true proportion of people who watched educational television.
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In a random sample of 198 people, 170 said that they watched
educational television. Find the...
In a random sample of 200 people, 154 said that they watched educational television. Find the...
In a random sample of 200 people, 154 said that they watched educational television. Find the 90% confidence interval of the population proportion of people who watched educational television. Which formula will you use for this problem? O3 -1.14( ) <-<a+bala ) On= (*12:0) On=p:4 () Oộ - - - - - - Oz-za-(M) <r<+zar (M)
In random, independent samples of 400 adults and 325 teenagers who watched a certain television show,...
In random, independent samples of 400 adults and 325 teenagers who watched a certain television show, 244 adults and 159 teens indicated that they liked the show. Let P, be the proportion of all adults watching the show who liked it, and let P, be the proportion of all teens watching the show who liked it. Find a 95% confidence interval for P -P2. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round...
In random, independent samples of 200 adults and 400 teenagers who watched a certain television show,...
In random, independent samples of 200 adults and 400 teenagers who watched a certain television show, 98 adults and 224 teens indicated that they liked the show. Let p1 be the proportion of all adults watching the show who liked it, and let P2 be the proportion of all teens watching the show who liked it. Find a 90% confidence interval for pi-p2. Then complete the table below. carry your intermediate computations to at least three decimal places. Round your...
Suppose that a simple random sample of 145, 91 said they drink coffee in the morning....
Suppose that a simple random sample of 145, 91 said they drink coffee in the morning. Step 1 of 5: What is the sample proportion for people who drink coffee in the morning? Step 2 of 5: Do we have what we need to compute a confidence interval? Yes, it's binomial. Yes, n≥30. Yes, we have a simple random sample, it is binomial with n/.05 gives a value less than the number of people than that in the world, and...
In a random samples of 400 adults and 600 teenagers who watched a certain television program,...
In a random samples of 400 adults and 600 teenagers who watched a certain television program, 100 adults and 300 teenagers indicated that they liked it. Construct a 96% confidence interval for the difference in the proportions of all adults and all teenagers who watched the program and liked it.
Based on a sample of 330 people, 170 said they prefer "Trydint" gum to "Eklypse". The...
Based on a sample of 330 people, 170 said they prefer "Trydint" gum to "Eklypse". The point estimate is: (to 3 decimals) The 95 % confidence interval is: to (to 3 decimals)
Suppose that a simple random sample of 121 people finds that 40 eat chocolate every day....
Suppose that a simple random sample of 121 people finds that 40 eat chocolate every day. Use this information to answer the following. A)What is the sample proportion for people who each chocolate every day? B)Do we have what we need to compute a confidence interval? Be sure to include your reasoning for full credit. C)Find the lower bound for a 98% confidence interval of the true proportion of people who eat chocolate daily, accurate to 3 decimal places. D)Find...
In a random sample of 100 people, 49 consider themselves as football fans. Compute a 92%...
In a random sample of 100 people, 49 consider themselves as football fans. Compute a 92% confidence interval for the true proportion of people consider themselves as football fans and fill in the blanks appropriately. We are % confidence that the true proportion of people consider themselves as football fans is between and . (Keep 3 decimal places)
In a random sample of 80 people, 36 consider themselves as baseball fans. Compute a 92%...
In a random sample of 80 people, 36 consider themselves as baseball fans. Compute a 92% confidence interval for the true proportion of people consider themselves as baseball fans and fill in the blanks appropriately. We are ____% confidence that the true proportion of people consider themselves as baseball fans is between ____ and ____ . (Keep 3 decimal places)
A random sample of 500 people is taken. 260 of them rent (as oppose to own)...
A random sample of 500 people is taken. 260 of them rent (as oppose to own) their residence. Compute a 95% confidence interval for the true proportion of people who rent their residence. Enter the upper bound of this confidence interval. Round your answer to two decimal places.
In a random sample of 200 people, 154 said that they watched educational television. Find the 90% confidence interval of the population proportion of people who watched educational television. Which formula will you use for this problem? O3 -1.14( ) <-<a+bala ) On= (*12:0) On=p:4 () Oộ - - - - - - Oz-za-(M) <r<+zar (M)
In random, independent samples of 400 adults and 325 teenagers who watched a certain television show, 244 adults and 159 teens indicated that they liked the show. Let P, be the proportion of all adults watching the show who liked it, and let P, be the proportion of all teens watching the show who liked it. Find a 95% confidence interval for P -P2. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round...
In random, independent samples of 200 adults and 400 teenagers who watched a certain television show, 98 adults and 224 teens indicated that they liked the show. Let p1 be the proportion of all adults watching the show who liked it, and let P2 be the proportion of all teens watching the show who liked it. Find a 90% confidence interval for pi-p2. Then complete the table below. carry your intermediate computations to at least three decimal places. Round your...
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