Question

(1 point) Based on information from Diagnostic Tests with Nursing Implications, Springhouse Corporation, for the population of healthy female adults, the mean red blood cell count (RBC) is 4.8 (millions of cells per cubic millimeter of whole blood). A researcher thinks the RBC is underestimated, so she conducts a test of significance using Null Hypothesis: u s 4.8 vs. Alternative Hypothesis: ? > 4.8. If the true mean RBC is 4.75 and the null hypothesis is rejected, what has occurred? A. No error has occurred B. Type II Error has occurred C. An error in the z-test statistic occurred D. Type I Error has occurred E. Cant tell without knowing the degrees of freedom 8. 9. (1 point) statistic of 1.45. Would you have the same conclusion if a 05 as you would with an a 10? A. True B. False You conduct a right-tailed one sample proportion test (with n>30) and find a z-test 10. (1 point) Suppose we want to test the hypothesis H.. ? = 5 vs. ?#5. Based on a random 2.32, what will be the correct statement about sample of size 15 we obtain the test statistic the p-value for this test? A. p-value -0.02 B. 0.02 <p-value <0.05 C. p-value 0.99 D. 0.01<p-value <0.025 E. 0.05 p-value <0.01 LI.(I point) We want to make a comparison on the proportion of deaths due to lung cancer in the plant workers versus the proportion of deaths due to lung general population of chemical cancer for those working in a new chemical plant. If we draw a sample and find the of deaths due to lung cancer in the general population of chemical estimated at 12.8% (n 250). Suppose that of 100 deaths that plant workers nationwide is occurred in a new chemical plant, 22 were found to be due to lung cancer. We wish to determine whether there is a difference between the proportion of deaths from lung cancer in this plant and the proportion in the general population of chemical plant workers. The hypotheses for this test are Ho: p 0 vs. HA: P1-P2 * 0, Anda-005. What is the SE for the difference in proportions? A. -0.0013 B. 0.0017 C. 0.0465 D. 0.2037 E. 0.0004
0 0
Add a comment Improve this question Transcribed image text
Answer #1

(8)

This is the case of incorrect rejection of a null hypothesis which is actually true, so this is actually a type I error.

(9)

False, because when the value of significance level decreases, the chances of rejection of null hypothesis are also reduced.

(10)

The p-value for this test is:

p = 0.0359

So the correct option is:

(B) 0.02 < p < 0.05

(11)

First we calculate the weighted proportion as follows:

p = (p1*n1 + p2*n2)/(n1+n2) = (0.128*250 + 0.22*100)/(250+100) = 0.154

The standard error is calculated as:

SE = ( p*(1-p)/n1 + p*(1-p)/n2 )0.5 = ( 0.154*(1-0.154)/250 + 0.154*(1-0.154)/100 )0.5 = 0.0427

So the closest answer is 0.0465

Hope this helps !

Add a comment
Know the answer?
Add Answer to:
(1 point) Based on information from Diagnostic Tests with Nursing Implications, Springhouse Corporation, for the population...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • We want to make a comparison on the proportion of deaths due to lung cancer in...

    We want to make a comparison on the proportion of deaths due to lung cancer in the general population of chemical plant workers versus the proportion of deaths due to lung cancer for those working in a new chemical plant. We draw a sample and find the proportion of deaths due to lung cancer in the general population of chemical plant workers nationwide is estimated at 12.8% (n=250). Suppose that of 100 deaths that occurred in a new chemical plant,...

  • The proportion of deaths due to lung cancer in males ages 15-64 in England and Wales...

    The proportion of deaths due to lung cancer in males ages 15-64 in England and Wales during the period 1970- 1972 was 12%. Suppose that of 20 deaths that occur among male workers in this age group who have worked for at least 1 year in a chemical plant, 5 are due to lung cancer. We wish to determine whether there is a difference between the proportion of deaths from lung cancer in this plant and the proportion in the...

  • 2) (5.5 points) Reports have shown that the proportion of deaths due to cancer in the...

    2) (5.5 points) Reports have shown that the proportion of deaths due to cancer in the U.S.is 20%. A researcher wants to examine whether workers in U.S. nuclear power plants have an increased proportion of deaths due to cancer compared to the national average. A hypothesis test was conducted at a 5% significance level. a) (1 point) What is the outcome variable? Is this outcome variable considered to be continuous or dichotomous? b) (2 points) State the null and alternative...

  • Problem: Proportion of "Cured” Cancer Patients: How Does Canada Compare with Europe? Lung cancer remains the...

    Problem: Proportion of "Cured” Cancer Patients: How Does Canada Compare with Europe? Lung cancer remains the leading cause of cancer death for both Canadian men and women, responsible for the most potential years of life lost to cancer. Lung cancer alone accounts for 28% of all cancer deaths in Canada (32%. in Quebec). Most forms of lung cancer start insidiously and produce no apparent symptoms until they are too far advanced. Consequently, the chances of being cured of lung cancer...

  • In a certain population of at risk patients, 5.2% ultimately die of a cardiovascular event in a five year window. A new...

    In a certain population of at risk patients, 5.2% ultimately die of a cardiovascular event in a five year window. A new medicine is developed with the hope of reducing the rate of death due to a cardiovascular event. A random sample of 2000 people from the population of at risk patients was taken and given the new medicine for five years. It was found that 82 of them died from a cardiovascular event. Is there evidence that the new...

  • In a certain population of at risk patients, 5.2% ultimately die of a cardiovascular event in...

    In a certain population of at risk patients, 5.2% ultimately die of a cardiovascular event in a five year window. A new medicine is developed with the hope of reducing the rate of death due to a cardiovascular event. A random sample of 2000 people from the population of at risk patients was taken and given the new medicine for five years. It was found that 82 of them died from a cardiovascular event. Is there evidence that the new...

  • (1 point) A sample of 6 measurments, randomly selected from a normally distributed population, resulted in...

    (1 point) A sample of 6 measurments, randomly selected from a normally distributed population, resulted in a sample mean x = 7.5 and sample standard deviation s = 1.08. Using a = 0.01, test the null hypothesis that the mean of the population is 8.1 against the alternative hypothesis that the mean of the population is less than 8.1 by giving the following: (a) the degree of freedom (b) the critical t value (c) the test statistic The final conclusion...

  • SHOW ALL WORK AND CHECK ANSWER. This problem is based on information taken from The Merck...

    SHOW ALL WORK AND CHECK ANSWER. This problem is based on information taken from The Merck Manual (a reference manual used in most medical and nursing schools). Diltiazem is a commonly prescribed drug for hypertension. However, diltiazem causes headaches in about 12% of patients using the drug. It is hypothesized that regular exercise might help reduce the headaches. If a random sample of 211 patients using diltiazem exercised regularly and only 19 had headaches, would this indicate a reduction in...

  • In order to conduct a hypothesis test for the population proportion, you sample 440 observations that...

    In order to conduct a hypothesis test for the population proportion, you sample 440 observations that result in 220 successes. (You may find it useful to reference the appropriate table: z table or t table Ho: p 0.52; HA: P 0.52 a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Test statistic a-2. Find the p-value....

  • n order to conduct a hypothesis test for the population proportion, you sample 480 observations that...

    n order to conduct a hypothesis test for the population proportion, you sample 480 observations that result in 264 successes. (You may find it useful to reference the appropriate table: z table or t table) Ho: pz 0.60 HA: p0.60 a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Test statistic 2.24 a-2. Find the p-value....

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT