1) Find the wavelength of a sound wave which has a frequency of 410 Hz. The speed of sound is 343 m/s.
2) Consider light with a wavelength equal to 576 nm. The speed of light is 3.00
1,
f = 410 Hz
v= 343 m/s
Now,
wavelength = v/f = 343 / 410 = 0.8365 m
2.
wavelength = 576 nm = 576 x 10^-9 m
v = 3 x 10^8 m/s
(a) wavelength = v/f
f = v / wavelength
f = 3 x 10^8 / 576 x 10^-9
f = 5.2 x 10^14 Hz
Time Period (T) = 1 / f = 1/(5.2 x 10^14) = 1.92 x 10^-15 sec = 1.92 femtosecond.
3.
(a)
wavelength = v/f = 3 x 10^8 / 935 x 10^3 = 320.85 m
(b)
wavelength = v / f = 3 x 10^8 / 87.2 x 10^6 = 3.44 m
1) wl = v/f = 343/410 = 0.8365 m
2) a) f = 3x10^8 / 576x10^-9 = 5.2x10^14 Hz
b) 1/f = 1/(5.2x10^14) = 1.92x10^-15 sec
3) a) Frequency f= 935 kHz = 935 * 10 ^ 3 Hz
speed of light c = 3 * 10 ^ 8 m / s
wavelength w = c / f = 320.86 m
b) frequency f ' = 87.2 * 10 ^ 6 Hz
wavelength w' = c / f ' = 3.44 m
QUESTION 1) HERE WE NEED TO FIND THE VALUE OF THE WAVELENGTH .
LAMBDA = v/f = 343 m/s / 410 hz = 0.836585365 m ===================PART A) ANSWER)
QUESTION 2) INCOMPLETE INFORMATION PROVIDED.
1) Find the wavelength of a sound wave which has a frequency of 410 Hz. The...
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