Homework Answers
since volume is 1 L , initial concentration will be same as initial number of moles
Let's prepare the ICE table
[H2] [I2] [HI]
initial 0.7 0.7 0
change -1x -1x +2x
equilibrium 0.7-1x 0.7-1x +2x
Equilibrium constant expression is
Kc = [HI]^2/[H2]*[I2]
53.3 = (2*x)^2/(0.7-1*x)^2
sqrt(53.3) = (2*x)/(0.7-1*x)
7.3007 = (2*x)/(0.7-1*x)
5.11048-7.30068*x = 2*x
5.11048-9.30068*x = 0
x = 0.549
At equilibrium:
[HI] = +2x = +2* 0.549 = 1.10 M
Answer: 1.10 M
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