A pendulum with a bob of mass m is swinging. If the initial height of the bob is increased from h1 to 2(h1), then what is the velocity change?
Using conservation of energy
Velocity at h1
0.5 m v1^2 = mgh1
v1 = sqrt ( 2 mgh1)
If the height increased to twice
v2 = sqrt ( 2 mg h 1 * 2)
v2 = 1.414* v1
I. E velocity increased by factor of sqrt(2)
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