Question

5.00 (0.00500 kg) bullised into 1.00 kw wooden pendulum it. After the collision, the pendulum and bullet swing upwan cm 120 m). Determine the initial of the baby doing the follows fed into a 1.00 ke wed b and becomes embedded um and bullet swing upward and reach a maximum height of 12.0 While the pendulum bob and bullet are swinging up the system. net are swinging upwards by 12 cm. mechanical energy is conserved in A. What is the final potential energy of the bob bullet system? B. What is the final kinetic energy of the bob/bullet system? C. What is the initial potential energy of the bob bullet system? D. What is the initial kinetic energy of the bob bullet system? E. What is the initial velocity of the bob/bullet system? While the bullet is colliding with the bob, momentum is conserved in the system. F. What is the final momentum of the system (before the bob starts swinging upward? G. What is the initial momentum of the bullet before the collision? H. What is the initial velocity of the bullet before the collision?

Answer 1

h= 012 m А@э refosence level M2 bullet m, = mass. 0.005 kg . Iuitial veloei twityal, ,Initial velocity Vz =8 [rest) Afler bultet embedded, mass f the bob My = M, + mz bob mz = mass (A) At point B ie. at mays imum height h= 0.12 m, ifinel. P.E = 1.005 X9-8X 012 = 1·182 J Mygh (B) At point B the final velocity nill be Hence Зело (c) At Roint A initial p.E kor h=o rill be (d) At Print A initial k. E nill be le) Applying law g lonservation g emryy Total eny (uétPc) at B (KE- +PE)at A Tstal eneryy = 1-182 U = 1-53 mls

() Applying law 3 Lonseuntion og momentum before ollision m,U, + M2V2 = m, V4 D.00 S XV, + 1xo = 1.005X 1·53 - 307.53 mls O.005 final momenteum (F) 8 the systemm = 1.005 X 1-53 (G) Initial momentem the bullet = 0.00S x 307.53 = 1•54 kg mls