Question

A 260 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.170 s. The total mechanical energy of the spring–load system is 5.00 J.

(a) What is the spring constant (in N/m)?

  N/m

(b) What is the amplitude (in m) of the motion?

  m

(c) What If? What is the percentage change in amplitude of motion if the total energy of the system is increased to 6.00 J?

% change =   

Answer 1

T= 27 mo 72 spring constant 4 m 45 (0.260) o. 1782 354.6 m E = KA2 5 354.8A A 10 354.8 20:1687 © E & A² Yu A2 1.095 1+0.095 A A2 -= 0.095 0.09) A2-A, A, ***100 = 0.095x100 = 9.5.). percentage of change in amplitude is 9.5%