Homework Answers
The FBD's of the two members are as shown below:
1) We first isolate member AD at joint C
applying c.o.e we get,
?MA = 0
100 x (11-3) - Cy x 16 + 100(28+3) = 0
Cy = 243.75 lbs
?Fx = 0
Ax = Cx ...........(i)
?Fy = 0
Ay -100 + 243.75 -100 = 0
Ay = 43.75 lbs
2) Now, we isolate member EC at pin C
again applying c.o.e we get,
?ME= 0
-100(11-3) + Cy*16 + Cx * 8 = 0
-100*8 + 243.75 x 16 + Cx * 8 = 0
Cx = -387.5 lbs
?Fx = 0
Ex = Cx = -387.5 lbs
?Fy = 0
-Ey +100 -243.75 = 0
Ey = -143.75 lbs
also, from (i)
Ax = -387.5 lbs
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