I need help finding the E cell! I keep getting it wrong!
Homework Answers
a)
from data table:
Eo(Co2+/Co(s)) = -0.28 V
Eo(Sn2+/Sn(s)) = -0.14 V
the electrode with the greater Eo value will be reduced and it will be cathode
here:
cathode Sn(II)
anode is Co(II)
Eocell = Eocathode - Eoanode
= (-0.14) - (-0.28)
= 0.14 V
Answer: 0.14 V
c)
from data table:
Eo(Cd2+/Cd(s)) = -0.40 V
Eo(Au3+/Au(s)) = 1.50 V
the electrode with the greater Eo value will be reduced and it will be cathode
here:
cathode is Au(III)
anode is Cd(II)
Eocell = Eocathode - Eoanode
= (1.50) - (-0.40)
= 1.90 V
Answer: 1.90 V
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I need help finding the E cell! I keep getting it wrong!
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