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0.96/1.91 POINTS PREVIOUS ANSWERS BBUNDERSTAT12 6.3.023. Find the z value such that 94% of the standard normal curve lies bet

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Answer #1

X=μ+Z×σ  

Solution :

Given that,

Using standard normal table,

P(-z < Z < z) = 94%
P(Z < z) - P(Z < z) = 0.94
2P(Z < z) - 1 = 0.94
2P(Z < z ) = 1 + 0.94
2P(Z < z) = 1.94
P(Z < z) = 1.94 / 2
P(Z < z) = 0.97
z = 1.88 and z = -1.88

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