Question

Saturn's largest moon, Titan is actually larger than the planet Mercury. It is also one of the few bodies in the solar system that has a dense atmosphere. Data from the Voyager 1 probe indicates that the atmospheric pressure on Titan's surface is about 1.60x10^5 Pa, even though free-fall acceleration at Titan's surface is only 1.36m/s^2. Assuming that Titan's atmosphere has a uniform density of 2.32kg/m^3, at what height above the surface is Titan's atmospheric pressure equal to 1.01x10^5 Pa?

Answer 1

P_h = P_0 - Rho gh 1.01 times 10^5 = 1.6 times 10^5 - 2.32 times 1.36 times h h = (1.6 - 1.01) times 10^5/2.32 times 1/36 h = 18699.3 m