Homework Answers
Yes, the computer's pyhsical memory address space can be larger than process's virtual memory address space.
Let's say we are working with a system that has 40 physical address bits. The total physical address space (assuming byte-addressable memory) is 240240 bytes, or 1 TiB. And if virtual addresses are 48 bits in length, that means there are more addresses available to virtual memory than there are locations in physical memory.
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11. In a paged virtual memory system, can the computer 's physical memory address space be...
17. A computer system implements a paged virtual memory system. Assume a 16-bit virtual address space...
17. A computer system implements a paged virtual memory system. Assume a 16-bit virtual address space and a 24-bit physical address space. Assume that the first 6 bits of a virtual address index the page table and the rest of the bits are the page offset. A process has the following indexed page table. Index Page Table Entry (PTE) 0x3800 0x3600 0x3200 0x1000 2 3 Each page table entry qives a hexadecimal page frame addresses. Translate the following two hexadecimal...
SN 6 A system implements a paged virtual address space for each process using a one-level...
SN 6 A system implements a paged virtual address space for each process using a one-level page table. The maximum size of virtual address space is 4KB. The page table for the running process Includes the following valid entries: Virtual Virtual page 7 - Page frame 4 Virtual Virtual page 5 - Page frame 0 Virtual Virtual page 20 - Page frame 1 Virtual Virtual page 10 - Page frame 3 Virtual Virtual page 3 - Page frame 2 The...
A system implements a paged virtual address space for each process using a one-level page table....
A system implements a paged virtual address space for each process using a one-level page table. The maximum size of virtual address space is 8MB. The page table for the running process includes the following valid entries (the -> notation indicates that a virtual page maps to the givenpage frame, that is, it is located in that frame): Virtual page 2 -> Page frame4 Virtual page 4 -> Page frame 9 Virtual page 1 -> Page frame2 Virtual page 3...
Given a virtual memory configuration with: • 4 TB virtual memory space • 32 GB physical...
Given a virtual memory configuration with: • 4 TB virtual memory space • 32 GB physical memory space • 16 KB page size How many bits are needed for the virtual address? Choose... How many bits are needed for the physical address? Choose... How many bits in the address correspond to page offset bits? Choose... - How many bits will the virtual page number (VPN) be? Choose... - How many bits will the physical page number (PPN) be? Choose... →...
1) Given a virtual memory system with: virtual address 36 bits physical address 32 bits 32KB...
1) Given a virtual memory system with: virtual address 36 bits physical address 32 bits 32KB pages (15 bit page offset) Each page table entry has bits for valid, execute, read and dirty (4 bits total) and bits for a physical page number. a) How many bits in the page table? (do not answer in bytes!) Three digit accuracy is good enough. The exponent may be either a power of 2 or a power of 10. b) The virtual address...
Exercise l: Suppose that we have a virtual memory space of 28 bytes for a given process and physical memory of 4 page frames. There is no cache. Suppose that pages are 32 bytes in length. 1) How...
Exercise l: Suppose that we have a virtual memory space of 28 bytes for a given process and physical memory of 4 page frames. There is no cache. Suppose that pages are 32 bytes in length. 1) How many bits the virtual address contain? How many bits the physical address contain? bs Suppose now that some pages from the process have been brought into main memory as shown in the following figure: Virtual memory Physical memory Page table Frame #...
Consider a computer system in which a physical page number is 20 bits, a virtual page...
Consider a computer system in which a physical page number is 20 bits, a virtual page number is 50 bits, and a virtual address is 64 bits. What is the maximum amount of physical memory, in GiB, that this system could have?
Address Translation Question [8 points] Suppose a computing system uses paging with a logical add...
Address Translation Question
[8 points] Suppose a computing system uses paging with a logical
address of 24 bits and a
physical address of 32 bits. The page size is 4KB. Answer each of
the following. If an answer is a power of 2, you can leave it in
the form of a power of 2. ...
2. [20 points] Memory address translation and TLB performance [8 points] Suppose a computing system uses paging with a logical address of 24 bits...
18. You have a byte-addressable virtual memory system with a two-entry TLB, a 2-way set associati...
18. You have a byte-addressable virtual memory system with a two-entry TLB, a 2-way set associative cache, and a page table for a process P. Assume cache blocks of 8 bytes and page size of 16 bytes. In the system below, main memory is divided into blocks, where each block is represented by a letter. Two blocks equal one frame. Given the system state as depicted above, answer the following questions: a) How many bits are in a virtual address...
A certain computer provides its users with a virtual memory space of 2^32 bytes. The computer...
A certain computer provides its users with a virtual memory space of 2^32 bytes. The computer has 2^18 bytes of physical memory. The virtual memory is implemented by paging, and the page size is 4,096 bytes. A user process generates the virtual address 11123456 hexadecimal. a. How many entries are there in the page table? b. Explain how the system establishes the corresponding physical location.
17. A computer system implements a paged virtual memory system. Assume a 16-bit virtual address space and a 24-bit physical address space. Assume that the first 6 bits of a virtual address index the page table and the rest of the bits are the page offset. A process has the following indexed page table. Index Page Table Entry (PTE) 0x3800 0x3600 0x3200 0x1000 2 3 Each page table entry qives a hexadecimal page frame addresses. Translate the following two hexadecimal...
SN 6 A system implements a paged virtual address space for each process using a one-level page table. The maximum size of virtual address space is 4KB. The page table for the running process Includes the following valid entries: Virtual Virtual page 7 - Page frame 4 Virtual Virtual page 5 - Page frame 0 Virtual Virtual page 20 - Page frame 1 Virtual Virtual page 10 - Page frame 3 Virtual Virtual page 3 - Page frame 2 The...
Given a virtual memory configuration with: • 4 TB virtual memory space • 32 GB physical memory space • 16 KB page size How many bits are needed for the virtual address? Choose... How many bits are needed for the physical address? Choose... How many bits in the address correspond to page offset bits? Choose... - How many bits will the virtual page number (VPN) be? Choose... - How many bits will the physical page number (PPN) be? Choose... →...
Exercise l: Suppose that we have a virtual memory space of 28 bytes for a given process and physical memory of 4 page frames. There is no cache. Suppose that pages are 32 bytes in length. 1) How many bits the virtual address contain? How many bits the physical address contain? bs Suppose now that some pages from the process have been brought into main memory as shown in the following figure: Virtual memory Physical memory Page table Frame #...
Address Translation Question
[8 points] Suppose a computing system uses paging with a logical
address of 24 bits and a
physical address of 32 bits. The page size is 4KB. Answer each of
the following. If an answer is a power of 2, you can leave it in
the form of a power of 2. ...
2. [20 points] Memory address translation and TLB performance [8 points] Suppose a computing system uses paging with a logical address of 24 bits...
18. You have a byte-addressable virtual memory system with a two-entry TLB, a 2-way set associative cache, and a page table for a process P. Assume cache blocks of 8 bytes and page size of 16 bytes. In the system below, main memory is divided into blocks, where each block is represented by a letter. Two blocks equal one frame. Given the system state as depicted above, answer the following questions: a) How many bits are in a virtual address...
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