Question

In an acid-base titration, 40.0 ml. of H2SO, was completely neutralized by 20.54 mL of a 0.708 mol/L KOH solution. a) Write t

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Answer #1

The given reaction is an acid base reaction. The complete balanced equation for this reaction is as shown below.

H2SO4 (ago + 2KOH caqs kopcast a Hoo (1)

I believe that the question asked is to calculate the molar concentration of H2SO4 and not H2SO3. I believe it is a typographic error in the question.I have read H2SO3 as H2SO4 and done the calculations.

It is understood from the reaction that one mole of H2SO4 requires 2 moles of KOH for the complete neutralization or in other words one mole of KOH neutralizes 1/2 mole of H2SO4. The equation used for the calculation of concentration in a titration is

ax Nasou x Vyson = Moon * You. М. Nuse - NKou * Уком , , Given Nkon =0.708 molla. Vkov - Q-5ч ть so - цо-от-. On substitution

The 1/2 comes in the equation from the 1:2 stoichiometry of KOH and H2SO4 in the complete neutralization.

Q8. It is the reaction of paraffin with oxygen to form only CO2 and H2O. This process is called combustion. Hence the energy released is called enthalpy of cumbustion.

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