Question

Written Assignment #7 Two construction workers are standing on a beam which is 10.0 m long and has mass of 50.0 kg. The beam is supported by a bolt at one end and a wire at the other as shown. 70 kg 60 kg a) Find the tension in the wire. b) Find the force exerted by the bolt. 30° 3.00 m . 7.00 m Question to be submitted:

Answer 1

#7 Length of the buam is = 10 m. mass of the beam is M = 50 kg. m = 70 kg m2 = 60 kg. forme body diaguram of the beam is m₂9 ng mag mang 3 m 5 mm Im. 10 m.

where I be the tunsion in the string. Ry and Rn be the vertical and horizontal component of fource by the boilt. Since the beam is in balance so not fource on - the buam will be zuio . . in vertical direction from Newton's second law Ry + Tsumbo - mag + mg + mag m + M + m2 Ry + Tsino = ( 70 +50 + 60) ×9.8 Ry + T Simso = 1764 Ry & T Sinzo law direction from Newton's second in horizontal - (ii) Ra = T cos 30

T Sim 30 Ra Torzo mong " thing • (9) point Since the beam is in equilibrium so net tous que on the beam will be zuro. Now we take met tourque about the hinge = 0 7 - T Sin 30XL0 + m2 9 x + Mg x 5 m, qx3 7 = Tx 5 + 60x 9.8* 70x9.8×3 +5089.8 x 5 | Newton T = 1724.8 Now from equation () = 1764 Sim3o Ry & 1724.8

om I Ry = 901.6 Nonton now from equation (ii) Rx = 1724. 8 cop 30 Newton. Rx = 1493.72 is now fourca enuited by the bolt - F = R + Ry? F (1493.72]? + (901.6) ? E = 1744.72 | Newton.