The rms speed of the molecules of a gas at 147°C is 191 m/s. Calculate the mass of a single molecule in the gas.
Given
Vrms = 191 m/s
T = 147 C = 147 + 273 = 420 k
Let M is the molar mass of the gas.
we know, Vrms = sqrt(3*R*T/M)
Vrms^2 = 3*R*T/M
==> M = 3*R*T/Vrms^2
= 3*8.324*420/191^2
= 0.2875 kg/mol
mass of one moelcule, m = M/NA
= 0.2875/(6.023*10^23)
= 4.77*10^-25 kg <<<<<<<------------Answer
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