The flow rate was 1.00 mL/min and the column mobile phase volume was 1.80 mL. The...
The flow rate was 1.00 mL/min and the column mobile phase volume was 1.80 mL. The stationary phase volume was 0.140 mL. For the compound with the peak at 2.75 min, what was the partition coefficient between the gas phase and the stationary phase at 150 degree C.
Homework Answers
tm = 1.80 mL / 1.00 mL/min = 1.80 min
tR = 2.75 min
we know that,
K Vs/Vm = ( tR - tM )/ tM
K = (1.80/0.140) x ( (2.75-1.80 ) / 1.80 )
= 6.79
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