How much does a 0.40m long copper rod with a 6.7mm diameter stretch when one end is fixed and the other is pulled with a 1.1kN force?
Youngs modlulus Y of a material is given Y =
FL/ADL
A = area
Y of copper = 1.1 e 11
DL = change of length
L = original length
F = force
so here we apply
DL = FL/AY
DL = 1100 * 0.4/(1.1e11 * 3.14* (6.7/2)^2 *10^-6)
DL = 0.113 mm
youngs modulus
?L=(FL)/(AY)
?L=[(1100N)(0.4 m )]/[(pi(.00335)^2)(117x10^9 )
?L=1.046x10^-4m
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