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Question 1 5 pts η Σαν Σ:Σν Given for formula for the correlation coefficient = the formulations V- 22-(02) 92-()2 of the s
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Formula for the correlation coefficient, r, is given as -

Υ Y = ηΣτg - ΣτΣ! VnΣτ2 – (Σ)? γηΣυ? – (Συ)2

Also, the formula of the slope and intercept in the estimated simple linear regression model  y = mx + b

where   m = \frac {n \sum xy - \sum x \sum y} { n\sum x^{2} - (\sum x)^{2} }and   b = \bar{y}-m\bar{x}

Given data :

T y xy x^{2} y^{2}
1 15 15 1 225
5 21 105 25 441
8 13 104 64 169
15 9 135 225 81
16 4 64 256 16
21 1 21 441 1
25 2 50 625 4
Total \sum x = 91 \sum y = 65 \sum xy = 494 \sum x^{2} = 1637 \sum y^{2} = 937

Using the above information, we can find the correlation coefficient for the given data as -

n = 7

Υ Y = ηΣτg - ΣτΣ! VnΣτ2 – (Σ)? γηΣυ? – (Συ)2

  = \frac {7 (494)- (91)(65)} { \sqrt{ 7(1637) - (91)^{2} } \sqrt{ 7(937) - (65)^{2} } }

  = \frac {3458- 5915} { \sqrt{ 11459 - 8281 } \sqrt{ 6559 - 4225} }

  = \frac {-2457} { \sqrt{3178 } \sqrt{2334} }

  = -0.9021 (rounded to 4 decimal places)

Thus, the correlation coefficient for the given data is approximately -0.9021 .

  

  

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