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Question 2 Methane gas flows through a pipeline with a volumetric flow rate of 11 ft/s at a pressure of 153 atm and a tempera
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Given that Methane gas flows through a pipeline with a volumetric flow rate (Q) = 11 ftºs Pressure (P) = 153 atm. Temperatureby nie van der wals equation:- a,b values are givena from the table a: 581 ato (H3 12 Ilmol bo 0.685 ft loral atm por (1545)By solving this equation we get v = 1.856 ft3/ebmal. ve 1.856 16.04 Tv = 0.1157 44966) ..maus flow rate(m)s a 0.1157 m = 95.010919 153 = 7 (1545)(516) Fatm | T-0.4751) lbl ū lū+0.4751), 516 2016. 376.718 - 480.682 153 - ✓ -0.4751 ūlū+0.4751) 1534|(V-1.96 16.04 V = 0.122 ft3/06 .may flow rate (mm)= DU YO Te 0.122 m = 90.164 lb/sec)

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