Question

Practice: How many liters of a 0.200 M solution can be prepared from 1.50 grams of each of the solutes below? NaNO3 Lici CH,CH,OH

Answer 1

NaNO3 Molarity (M) = X. weight Molecular weight Volleve of the solution (inL) From the data M = 0.2M, wt = 1.50g . M. wt of NaNo== 85g/mol vwtxt 9. Wt ² M substitute all the values v= lsg xl 855/pop* od malih V = 0.088L 0.088L of solution can be prepared.

Lich Lici mowit = 42.49/mol M = 0.2M = 0.2 molle, ut = 1.59 v= wt xl - Mwt x L re-wt M v= 1.59 - X B 42.4%mol 0.2 mollit W = 0.177 Lit V = 0.18 Lit 0.18L of solution can be prepared

сҢ Сн,он SHg OH Molecular weight = 469/mol M: 0.2M, weight = wt = 1.59 vwt Mint v 1.59 46 g/mol 1 ona mol V= 0.163 eit 2 or 16 lit of ch choh solution can be prepared.