What number does each line of code print out? Briefly explain why. printf("%u\n",(unsigned char)(-2)); printf("%d\n",(unsigned char)(-2));...
What number does each line of code print out? Briefly explain why.
printf("%u\n",(unsigned char)(-2));
printf("%d\n",(unsigned char)(-2));
printf("%u\n",(uint16_t)(-2));
printf("%d\n",(uint16_t)(-2));
printf("%u\n",(unsigned int)(-2));
printf("%d\n",(unsigned int)(-2));
Homework Answers
printf("%u\n",(unsigned char)(-2));
unsigned char value of -2 converted to unsigned int is 254
printf("%d\n",(unsigned char)(-2));
unsigned char value of -2 converted to int is 254
printf("%u\n",(uint16_t)(-2));
uint16_t is unsigned 16-bit integer
unsigned 16-bit of -2 converted to unsigned int is 65534
printf("%d\n",(uint16_t)(-2));
unsigned 16-bit of -2 converted to int is 65534
printf("%u\n",(unsigned int)(-2));
unsigned int value of -2 converted to unsigned gives memory address
4294967294
printf("%d\n",(unsigned int)(-2));
unsigned char value of -2 converted to int is -2
Add Answer to:
What number does each line of code print out? Briefly explain
why.
printf("%u\n",(unsigned char)(-2));
printf("%d\n",(unsigned char)(-2));...
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C PROGRAM
When you print out the old and new bitsets, which are of type
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statement rather than %x or %d or %c. The compiler will complain,
but we don't always listen to them anyway. The difference is it
will print the bitset out in hex with a preceeding %0x.
unsigned char bitset = 0x14 ;
printf("Bitsrt is %p\n", bitset) ; results in Bitset is 0x14,
which is what...
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