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Question 2: [4+4+4+6] Two signals 9.(t) = 100rect(1001) and 92(t) = 8(1) are applied at the inputs of the ideal low pass filters .(1) = rect/200) and (0)=rect /100) as shown in Figure Q2. The outputs y, and y(t) of these filters are multiplied to obtain the signal y(t) = y(y(t). a) Sketch and G20). b) Sketch H and H2. c) Sketch Y. and Y21). d) Find the bandwidths of y(t).yz(t), and y(t). 8, () Hull y (1) = y; (0,0) Figure 02. Block diagram of a typical communication system

Answer 1

Q.2)

a).

gre) = 100 rect(toot) 8:0+) = 8Ct) @ Sketch Gill & Ge(6) Gulf) - s gift) & jarft dit - 11.200 S 100 e laco 360 janka -1200 = 100 janst 1 1200 - jant ) - 1.200 i jtit - il Tit) 10 / e looe 100 Titaj sin 8 . sint 10o = sincetoo) Gulb - 200 200

- Garb) - som gert) langt det - see e larse de Galf) = 1 A G2(E)

b).

6 sketch thi (f) & Half) HiCf) - yect (1/200) Hack) - red (t/co) 1oo 100 50 50

C).

© sketch yild) & Youp) Yi (6) = G(6) Hick) Y2 (8) = Gelf) tha (8) Vic) - 100 100 -50 SO

D).

Bandwidth of y2(t) =50hz