Question

2.0 kg 3.0 kg PROBLEM 4-8 points 2.0 kg In case 1 and case 2, the boxes are 5.0 kg 5.0 kg 3.0 kg subjected to the same constant force F F directed to the right. The surface is frictionless. Case 1 Case 2 [2 points] (a) Draw one free-body diagram, and use it to come up with an expression for the acceleration of the system. Be clear what you are drawing the free-body diagram of. [2 points] (b) For case 2, choose either one object or a set of objects so that the only horizontal force acting is the force applied by the 2.0 kg box on the 5.0 kg box. Draw a free-body diagram, and use your diagram to help you come up with an expression for that force, in terms of F only. F2-5, case 2 [3 points] (c) For case 1, what is the magnitude of the net force acting on the 5.0 kg box, the 2.0 kg box, and the 3.0 kg box, in terms of F only? We're looking for three separate answers! Fnets = Fnet,2 = Fnet,3 = [1 point] (d) If the force that the 5.0 kg box applies to the 2.0 kg box in case 2 is 24 N, what is the magnitude of F?

Answer 1

mo m2 m3 mi Fhmi - F-fiam, a m2 fortzamza For m2 1 Tito Forma 2 ta = mza solving all , as mama tmy) fi= (ma+m3) a f2= mza a toto m, 4 m2 are inter @ for case-2 Changed i. Ezusäses = (maamela = BF un ulu uogle logo co © Fret s = sa Finet z = za Faet 3 = 3a fi = (m2 + Mg) a = 24 (5+2) a =24 a=24 F = (m, + m2 + Mzja F = 10xze F = 240 = 34.3 N