Given that, n = 111 and x = 46
=> sample proportion = 46/111 = 0.4144
a-1) The null and alternative hypotheses are,
H0 : π ≤ 0.38 versus H1 : π > 0.38
critical value at significance level of 0.05 is, z* = 1.645
Decision Rule : Reject H0 if Zcalc > 1.645
a-2) Test statistic is,
=> Test statistic = 0.75
a-3) Since, test statistic = 0.75 < 1.645, we fail to reject the null hypothesis.
Answer : False
b) No, this is not close decision.
c) assumption is,
nπ > 10 and n(1 - π) > 10
Answer : c)
Chapter Exercise 9-86 A sample of 111 mortgages approved during the current year showed that 46...
Chapter Exercise 9-86 A sample of 103 mortgages approved during the current year showed that 45 were issued to a single-earner family or individual. The historical percentage is 37 percent. At the .05 level of significance in a right-tailed test, has the percentage of single-earner or individual mortgages risen? (a-1) H0: π ≤ .37 versus H1: π > .37. Choose the right option. Reject H0 if zcalc > 1.645 Reject H0 if zcalc < 1.645 a b (a-2) Calculate the...
A sample of 103 mortgages approved during the current year showed that 45 were issued to a single-earner family or individual. The historical percentage is 37 percent. At the .05 level of significance in a right-tailed test, has the percentage of single-earner or individual mortgages risen? A) H0: ππ ≤ .37 versus H1: ππ > .37. Choose the right option. 1 or 2 1. Reject H0 if zcalc > 1.645 2. Reject H0 if zcalc < 1.645 A2) (a-2)...
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