FOR N = 3
ANSWER QUESTION 11.
The parts above it are the previous exercise it mentions. For N = 3
11.
R: {(x,y)Z*Z : x-y divisible by n=3}
a)
now let y=x
so
relation x-y =x-x=0 and Zero is divisible by 3
so
relationship is follows for (x,x) Hence its reflexive
b)
now
if x-y divisible by n=3
so
-(x-y) =y-x is also divisible by 3
Hence
x R y => yRx
Hence its Symmetric
c)
let
there are 3 elements x,y,and u
x-y is divisible by 3
y-u is divisible by 3
now so
(x-y)+(y-u) =x-u is also divisible by 3
Hence this relation is transitive
d)
there are two partitions of Z*Z that is
[x] => {(x,y)Z*Z : x-y divisible by n=3}
[x] =>{(x,y)Z*Z : x-y not divisible by n=3}
FOR N = 3 ANSWER QUESTION 11. The parts above it are the previous exercise it...
1) Let R be the relation defined on N N as follows: (m, n)R(p, q) if and only if m - pis divisible by 3 and n - q is divisible by 5. For example, (2, 19)R(8,4). 1. Identify two elements of N X N which are related under R to (6, 45). II. Is R reflexive? Justify your answer. III. Is R symmetric? Justify your answer. IV. Is R transitive? Justify your answer. V.Is R an equivalence relation? Justify...
Please do exercise 129: Exercise 128: Define r:N + N by r(n) = next(next(n)). Let f:N → N be the unique function that satisfies f(0) = 2 and f(next(n)) =r(f(n)) for all n E N. 102 1. Prove that f(3) = 8. 2. Prove that 2 <f(n) for all n E N. Exercise 129: Define r and f as in Exercise 128. Assume that x + y. Define r' = {(x,y),(y,x)}. Let g:N + {x,y} be the unique function that...
Exercise 1.6.4: Prove the following by induction: (a) “k - n(n+1)(2n +1) k= 1 (b) If n > 1, then 13-n is divisible by 3. (c) For n 3, we have n +4 <2". (d) For any positive integer n, one of n, n+2, and 11+ 4 must be divisible by 3. (e) For all n e N, we have 3" > 2n +1. ()/Prove that, for any x > -1 and any n e N, we have (1+x)" 21+1x.
Exercise 8 . Let n = 5-11-12 = 660. (A) Find i < y < n such that 1 mod(5), 3 mod(11), y 11 mod(12). (B) Suppose r E Z such that 4 mod(5) and 8 mod ( (11) Briefly explain why 55 divides +y, where y is the number from Part Show that, for all nEN, Exercise 9. 13 (29" -3")
ANSWER 5,6 & 7 please. Show work for my understanding and upvote. THANK YOU!! Problem 5. (3 pts) Let {x,n} be a bounded sequence of real numbers and let E = {xn : n E N}. Prove that lim inf,,0 In and lim inf, Yn are both in E. Hint: Use the sequential characterization of the closure, i.e., Proposition 3.2 from class. Problem 6. (3 pts) As usual let Q denote the set of all rational numbers. Prove that R....
Exercise 7 (2 points) Recall the binomial coefficient for integer parameters 0 Sk< n. Prove that Exercise 8 (2 points) Prove the following: if z is an integer with at most three decimal digits aia2a3, then x is divisible by 3 if and only if aut a2 +a3 is divisible by 3. Exercise 9 (3 points) A square number is an integer that is the square of another integer. Let x and y be two integers, each of which can...
4. Define a function f:N → Z by tof n/2 if n is even 1-(n + 1)/2 if n is odd. f(n) = Show that f is a bijection. 11 ] 7. Let X = R XR and let R be a relation on X defined as follows ((x,y),(w,z)) ER 4 IC ER\ {0} (w = cx and z = cy.) Is R reflexive? Symmetric? Transitive? An equivalence relation? Explain each of your answers. Describe the equivalence classes [(0,0)]R and...
4. [3 marks] Let R be a relation on a set A. Let A {1,2, 3, X, Y} and R = {(1, 1), (1,3), (2,1), (3, 1), (1, X), (X, Y)} (a) What is the reflexive closure of R? (b) What is the symmetric closure of R? (c) What is the transitive closure of R?
Please answer the parts 6 and 7. Thank you. 2. In this problem, we will prove the following result: If G is a group of order 35, then G is isomorphic to Zg We will proceed by contradiction, so throughout the following questions, assume that G is a group of order 35 that is not cyclic. Most of these questions can he solved independently I. Show that every element of G except the identity has order 5 or 7. Let...
This is the previous question, Pls answer this question, Let f : [0, 1] + R be uniformly continuous, so that for every e > 0, there exists 8 >0 such that |x – y<8\f(x) – f(y)] < € for every x, y = [0, 1]. The graph of f is the set G = {(x, f(x)) : x € 0,1} Show that Gf has measure zero Let f : [0, 1] [0, 1] + R be defined by f(x,y)...