Question

If a patient\'s blood pressure is 115 over 85 mmHg, what is it in atmospheres (atm)?

At 1 atm, how much energy is required to heat 63.0 g of H2O(s) at –12.0 °C to H2O(g) at 147.0 °C?

Answer 1

esiven. Is mm ng datm = 760 mm ng . 115 mm kg = R15, alm. 85 mury Hg = 0.112 atm. the ois homes 0.11 2 atm - blood pressure.

Specific cheut of water/ liquid) = 4.186 T/ge specific heat of wates Lice) = 2011 J/g °C specific heat of water vapous) = 2.0 F/goc enthalpy of fision = 334 5/9. I heat of vaporization 22.2305 g.

1 K2O(s) at -12% to at_1479 it connest in a steps such as i t 0 -12°C 7 0°C (opecific heat of waberelice)] o oo _ 0° / enthalpy of fasion) [ice swotos] @ 0° -100°C (specific heat of water liquid)] @ 1002 100% renthalpy of vaporization) [liquid vapres) @ 100% -2147% (opecific heat of vapour) - That, heat required to Q = 6338 (0-C-12) € x 2.11 Ilgºc + 639 x (3341/4) + 63 x 100°C X 4.186 Tla'c + 63 x 2230 + L 63 x (147 -100) x2 J/g °C 195.42 KJ