Question

1. Write a quadratic equation that has integer coefficients and has as solutions the given pair of numbers. (Use x as the variable.)

and 5

2

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2. Evaluate $-b + \sqrt{b^2-4ac}$ for the given values of a, b, and c. Write the result as a complex number.

a = ?4, b = 2, c = ?5

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Answer 1

The Quadratic function is -5/9 and 5 There f(x) = (x + 5/9) . (x - 5) - Quadratic equation has solution of - 5/9 and 5 Therefore (x + 5/9) and (x - 5) must be factor of Quadratic function f(x) = (x + 5/9) (x - 5) f(x) = x^2 - 5x + 5/9 x - 25/9 f(x) = x^2 - 40/9 x - 25/9 a = -4: b = 2: x = -5 evaluating - b + squareroot b^2 - 4ac rightarrow - 2 + squareroot 4 - 4(- 4) (- 5) rightarrow - 2 + squareroot 4 - 80 rightarrow - 2 + squareroot - 76 rightarrow - 2 + i2 squareroot 19 Ans