Question

Write a program to solve the quadratic equation ax^2 + bx + c = 0 using the standard quadratic formula x = -b plusminus Squareroot b^2 - 4ac/2a or the alternative formula x = 2c/-b Squareroot b^2 - 4ac. Your program should accept values for the coefficients a, b, and c as input and produce the two roots of the equation as output. Your program should detect when the roots are imaginary, but need not use complex arithmetic explicitly. You should guard against unnecessary overflow, underflow, and cancellation. When should you use each of the two formulas? Try to make your program robust when given unusual input values. Any root that is within the range of the floating-point system should be computed accurately, even if the other is out of range. Test your program using the following values for the coefficients:

please answer this question with python.

Answer 1

1.10 Solution Program to find the quadratic equation using python according to the given values of A,B and C #70 solve quadratic equation AXA2-BX+C=0 #import math module import cmath a-6 c-4 #10 take in ser #a-float(input('enter a value')) #b-float(input('enter b value)) #c=float(input('enter c value:')) # to find the discremínant use d-(b^2)-(4 *a*c) # to find the standard solution using the below formula: put values from the u if d<0 print(Imaginary roots,) elif d == 0 x 1=((-b) + sqrt(b-2-4* a*c)/2*a print(It has one real solution', x1) else x2-((-b) + sqrt(b-2-4 *a"c)/2*a print(The solution of the equation are:0} and (l)y. format(x2,x3))