Question

CSC 211 - Lab-2 Write a C++ program to find the roots of a quadratic equation ax +bx+c=0. The roots are given by the formula, x=-b I56²-4ac 2a x = -b+ √b²-4ac 2. x2 = -b-√6²-4ac 2a Instructions: 1. Type, compile, and run the program in an online C++ compiler. 2. Open a word document and copy the following items onto it: a. The source code b. Screenshot of your program's result 3. Save the word document as lastnameFirstname_Lab2.docx (for example my lab2 will be Swamidurai Rajendran_lab2.docx). Alternatively, you can save it as a .pdf file as well. 4. Upload the file in Blackboard and submit it.

Answer 1

#include<stdio.h>
#include<bits/stdc++.h> 
using namespace std; 


int main() 
{ 
        int a,b,c;
        cout<<"Enter the value of a : ";
        cin>>a;
        cout<<"Enter the value of b : ";
        cin>>b;
        cout<<"Enter the value of c : ";
        cin>>c;
        if (a == 0) 
        { 
                cout << "Invalid"; 
        } 

        int discriminant = b*b - 4*a*c; 
        double s = sqrt(abs(discriminant)); 

        
        if (discriminant == 0) 
        { 
                cout << "Roots are real and same \n"; 
                cout <<"Root = "<<-(double)b / (2*a); 
        }
        
        else if(discriminant < 0) 
        { 
                cout << "Roots are complex \n"; 
                cout << "Root 1 = "<< -(double)b / (2*a) << " + i" << s << "\n" <<"Root 2 = "<<-(double)b / (2*a) << " - i"<< s; 
        }  
        else
        { 
                cout << "Roots are real and distinct \n"; 
                cout <<"Root 1 = " <<(double)(-b + s)/(2*a) << "\n"<<"Root 2 = "<<(double)(-b - s)/(2*a); 
        } 
        return 0; 
} 

The above is the code that asks the user to enter the a,b,c values in a quadratice equation and then it will check if a=0 then if a =0 it prints invalid else it will caculate the discriminant and check if it is =0 or <0 or >0.If it is equal to 0 then it prints " Roots are equal" and the root and if <0 it prints "Roots are complex" and the roots and if >0 then it prints rools are real and distinct and print the roots.

HERE INTENDATION IS NOT NEEDE IN C++ SO IAM NOT PROVIDING THE SCREENSHOT OF THE CODE AND ALSO I CANNOT GIVE IT IN A TEXT FILE AS THERE IS NO OPTION TO GIVE TEXT FILE.

SCREENSHOT OF THE OUTPUT:

FOR EQUAL ROOTS (D=0):

input Enter the value of a 1 Enter the value of b: - 4 Enter the value of c: 4 Roots are real and same Root = 2 codd o ... Program finished with exit co Press ENTER to exit console. I

FOR REAL AND DISTINCT(D>0)

input Enter the value of a : 1 Enter the value of b: -5 Enter the value of c: 6 Roots are real and distinct Root 1 = 3 Root 2 = 2 ... Program finished with exit code o Press ENTER to exit console.

FOR IMAGINARY ROOTS OR COMPLEX ROOTS(D<0):

Enter the value of a : 1 Enter the value of b: 4 Enter the value of c: 5 Roots are complex Root 1 = -2 + i2 Root 2 = -2 i2 I ... Program finished with exit code 0 Press ENTER to exit console.