Question

In Python.

The two roots of a quadratic equation ax^2 + bx + c = 0 can be obtained using the following formula: r1 = (-b + sqrt(b^2 - 4ac) / (2a) and r2 = (-b - sqrt(b^2 - 4ac) / (2a) b^2 - 4ac is called the discriminant of the quadratic equation. If it is positive, the equation has two real roots. If it is zero, the equation has one root. If it is negative, the equation has no real roots.

Write a program that prompts the user to enter values for a, b, and c and displays the result based on the discriminant. If the discriminant is positive, display two roots. If the discriminant is 0, display one root.

Otherwise, display “The equation has no real roots”.

Answer 1

print('Finding roots of ax^2 + bx + c = 0')

a = float(input('Enter a value of a: '))
b = float(input('Enter a value of b: '))
c = float(input('Enter a value of c: '))

d = b*b - 4*a*c

if d == 0:
    print('Root is', -b/(2*a))
elif d < 0:
    print('The equation has no real roots.')
else:
    d = d**0.5
    r1 = (-b + d) / (2 * a)
    r2 = (-b - d) / (2 * a)
    print('Roots are', r1, 'and', r2)